Return FileName Only when using OpenFileDialog

Question

I am using the following method to browse for a file:

    OpenFileDialog.ShowDialog()
    PictureNameTextEdit.Text = OpenFileDialog.FileName

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Answer 1

Suppose that I did select word2010 file named as "MyFileName.docx"

This is for ONLY the selected file extension "including the dot mark, f.e (.docx)"

MsgBox(System.IO.Path.GetExtension(Opendlg.FileName))

And this for the selected File name without extension: (MyFileName)

MsgBox(System.IO.Path.GetFileNameWithoutExtension(Opendlg.FileName))

and you can try the other options for the "PATH Class" like: GetFullPath,GetDirectoryName ...and so on.

Answer 2

Use SafeFileName instead of FileName and it will return a name (and extension) without path.

Answer 3

if you want just the selected name without Extension you can try this code

Imports System.IO


PictureNameTextEdit.Text = Path.GetFileNameWithoutExtension(OpenFileDialog1.Fi‌​leName)

thanx

Answer 4

Use Path.GetFileName(fullPath) to get just the filename part, like this:

OpenFileDialog.ShowDialog()
PictureNameTextEdit.Text = System.IO.Path.GetFileName(OpenFileDialog.FileName)

Answer 5

Use this code to put the filename in PictureNameTextEdit:

OpenFileDialog.ShowDialog()
PictureNameTextEdit.Text = OpenFileDialog.SafeFileName

Answer 6

OpenFileDialog.ShowDialog()
PictureNameTextEdit.Text = System.IO.Path.GetFileName(OpenFileDialog.FileName)