Is there a way to get the last digit of a number. I am trying to find variables that end with \"1\" like 1,11,21,31,41,etc..
If I use a text variable I can simply pu
By using iteration and the in built function of 'digit' the number is treated as binary and so it goes from backwards to forwards. Here is an example of a bit of code for you.
for digit in binary:
denary= denary*2 + int(digit)
The simplest and most efficient way is to use the reminder :
last_digit = orginal_number % 10