How to check last digit of number

Question

Is there a way to get the last digit of a number. I am trying to find variables that end with \"1\" like 1,11,21,31,41,etc..

If I use a text variable I can simply pu

Answer 1

So you want to access the digits in a integer like elements in a list; easiest way I can think of is:

n = 56789
lastdigit = int(repr(n)[-1])
# >  9

Convert n into a string, accessing last element then use int constructor to convert back into integer.

For a Floating point number:

n = 179.123
fstr = repr(n)
signif_digits, fract_digits = fstr.split('.')
# >  ['179', '123']
signif_lastdigit = int(signif_digits[-1])
# >  9

Answer 2

Convert to string first:

oldint = 10101
newint = int(str(oldint)[-1:]) 

Answer 3

I can't add a comment yet, but I wanted to iterate and expand on what Jim Garrison said

Remainder when dividing by 10, as in numericVariable % 10

This only works for positive numbers. -12%10 yields 8

While modulus (%) is working as intended, throw on an absolute value to use the modulus in this situation.

abs(numericVariable) % 10

Answer 4

Use the modulus operator with 10:

num = 11
if num % 10 == 1:
    print 'Whee!'

This gives the remainder when dividing by 10, which will always be the last digit (when the number is positive).

Answer 5

Remainder when dividing by 10, as in

numericVariable % 10

This only works for positive numbers. -12%10 yields 8

Answer 6

Lostsoul, this should work:

    number = int(10)
#The variable number can also be a float or double, and I think it should still work.
lastDigit = int(repr(number)[-1])
#This gives the last digit of the variable "number." 
if lastDigit == 1 : 
    print("The number ends in 1!")

Instead of the print statement at the end, you can add code to do what you need to with numbers ending in 1.

Hope it helped!