Manipulating inline style with angular does not work in IE

Question

I wanted to set the position of a div based on the return value of a function in an angular controller

The following works fine in FireFox and in chrome but in Inter

Answer 1

If you want to use angular binding expression {{}} just like normal style attribute like style="width:{{someScopeVar}}", use ng-attr-style and it will work perfectly IE (and obviously other smarter ones) :)

check my jsFiddle ... Checked with Angular JS 1.4.8

here I have shown the usage of style, ng-style and ng-attr-style

THE HTML

<div ng-app="app">
    <div ng-controller="controller">

        <div style="background:{{bgColor}}">
            This will NOT get colored in IE
        </div>

        <div ng-attr-style="background:{{bgColor}}">
            But this WILL get colored in IE
        </div>

        <div ng-style="styleObject">
            And so is this... as this uses a json object and gives that to ng-style
        </div>

    </div>
</div>

THE JS

var app = angular.module('app', []);

app.controller('controller', function($scope) {

    $scope.bgColor = "yellow";        
    $scope.styleObject = {"background": "yellow"};
});

Answer 2

You must use ng-style instead of style, otherwise some browsers like IE will remove invalid style attribute values (presence of {{}} etc makes it invalid) before even angular has a chance to render it. When you use ng-style angular will calculate the expression and add the inline style attributes to it.

<div ng-repeat="item in items" ng-style="{left: position($index) + '%'}"></div>

Since you are anyways calculating the position you could as well add % from the position and send it. Also remember that calling a function in ng-repeat will invoke the function every digest cycle, so you may want to be careful not to do too much intensive operations inside the method.

 <div ng-repeat="item in items" ng-style="{left: position($index)}">{{item}}</div>

and return

  return percent[i+1] + "%";

Demo

Answer 3

Yes, ng-style will work to resolve this problem. You can use conditionally style using ternary operator.

HTML:

<div ng-style="{'display':showInfo?'block':'none'}">
</div>