Sum the digits of a number

Question

If I want to find the sum of the digits of a number, i.e.:

• Input: 932
• Output: 14, which is (9 + 3 + 2)

Answer 1

you can also try this with built_in_function called divmod() ;

number = int(input('enter any integer: = '))
sum = 0
while number!=0: 
    take = divmod(number, 10) 
    dig = take[1] 
    sum += dig 
    number = take[0] 
print(sum) 

you can take any number of digit

Answer 2

The best way is to use math.
I knew this from school.(kinda also from codewars)

def digital_sum(num):
    return (num % 9) or num and 9

Just don't know how this works in code, but I know it's maths

If a number is divisible by 9 then, it's digital_sum will be 9,
if that's not the case then num % 9 will be the digital sum.

Answer 3

You can try this

def sumDigits(number):
    sum = 0
    while(number>0):
        lastdigit = number%10
        sum += lastdigit
        number = number//10

    return sum

Answer 4

If you want to keep summing the digits until you get a single-digit number (one of my favorite characteristics of numbers divisible by 9) you can do:

def digital_root(n):
    x = sum(int(digit) for digit in str(n))
    if x < 10:
        return x
    else:
        return digital_root(x)

Which actually turns out to be pretty fast itself...

%timeit digital_root(12312658419614961365)

10000 loops, best of 3: 22.6 µs per loop

Answer 5

Try this

    print(sum(list(map(int,input("Enter your number ")))))

Answer 6

n = str(input("Enter the number\n"))

list1 = []

for each_number in n:

        list1.append(int(each_number))

print(sum(list1))