For example, how do I get Output.map
from
F:\\Program Files\\SSH Communications Security\\SSH Secure Shell\\Output.map
You can use the basename() function.
basename() has a bug when processing Asian characters like Chinese.
I use this:
function get_basename($filename)
{
return preg_replace('/^.+[\\\\\\/]/', '', $filename);
}
It's simple. For example:
<?php
function filePath($filePath)
{
$fileParts = pathinfo($filePath);
if (!isset($fileParts['filename']))
{
$fileParts['filename'] = substr($fileParts['basename'], 0, strrpos($fileParts['basename'], '.'));
}
return $fileParts;
}
$filePath = filePath('/www/htdocs/index.html');
print_r($filePath);
?>
The output will be:
Array
(
[dirname] => /www/htdocs
[basename] => index.html
[extension] => html
[filename] => index
)
With SplFileInfo:
SplFileInfo The SplFileInfo class offers a high-level object oriented interface to information for an individual file.
Ref: http://php.net/manual/en/splfileinfo.getfilename.php
$info = new SplFileInfo('/path/to/foo.txt');
var_dump($info->getFilename());
o/p: string(7) "foo.txt"
<?php
$windows = "F:\Program Files\SSH Communications Security\SSH Secure Shell\Output.map";
/* str_replace(find, replace, string, count) */
$unix = str_replace("\\", "/", $windows);
print_r(pathinfo($unix, PATHINFO_BASENAME));
?>
body, html, iframe {
width: 100% ;
height: 100% ;
overflow: hidden ;
}
<iframe src="https://ideone.com/Rfxd0P"></iframe>
$image_path = "F:\Program Files\SSH Communications Security\SSH Secure Shell\Output.map";
$arr = explode('\\',$image_path);
$name = end($arr);