Suppose I have a nested dictionary \'user_dict\' with structure:
In case someone wants to get the data frame in a "long format" (leaf values have the same type) without multiindex, you can do this:
pd.DataFrame.from_records(
[
(level1, level2, level3, leaf)
for level1, level2_dict in user_dict.items()
for level2, level3_dict in level2_dict.items()
for level3, leaf in level3_dict.items()
],
columns=['UserId', 'Category', 'Attribute', 'value']
)
UserId Category Attribute value
0 12 Category 1 att_1 1
1 12 Category 1 att_2 whatever
2 12 Category 2 att_1 23
3 12 Category 2 att_2 another
4 15 Category 1 att_1 10
5 15 Category 1 att_2 foo
6 15 Category 2 att_1 30
7 15 Category 2 att_2 bar
(I know the original question probably wants (I.) to have Levels 1 and 2 as multiindex and Level 3 as columns and (II.) asks about other ways than iteration over values in the dict. But I hope this answer is still relevant and useful (I.): to people like me who have tried to find a way to get the nested dict into this shape and google only returns this question and (II.): because other answers involve some iteration as well and I find this approach flexible and easy to read; not sure about performance, though.)
Building on verified answer, for me this worked best:
ab = pd.concat({k: pd.DataFrame(v).T for k, v in data.items()}, axis=0)
ab.T
A pandas MultiIndex consists of a list of tuples. So the most natural approach would be to reshape your input dict so that its keys are tuples corresponding to the multi-index values you require. Then you can just construct your dataframe using pd.DataFrame.from_dict
, using the option orient='index'
:
user_dict = {12: {'Category 1': {'att_1': 1, 'att_2': 'whatever'},
'Category 2': {'att_1': 23, 'att_2': 'another'}},
15: {'Category 1': {'att_1': 10, 'att_2': 'foo'},
'Category 2': {'att_1': 30, 'att_2': 'bar'}}}
pd.DataFrame.from_dict({(i,j): user_dict[i][j]
for i in user_dict.keys()
for j in user_dict[i].keys()},
orient='index')
att_1 att_2
12 Category 1 1 whatever
Category 2 23 another
15 Category 1 10 foo
Category 2 30 bar
An alternative approach would be to build your dataframe up by concatenating the component dataframes:
user_ids = []
frames = []
for user_id, d in user_dict.iteritems():
user_ids.append(user_id)
frames.append(pd.DataFrame.from_dict(d, orient='index'))
pd.concat(frames, keys=user_ids)
att_1 att_2
12 Category 1 1 whatever
Category 2 23 another
15 Category 1 10 foo
Category 2 30 bar
So I used to use a for loop for iterating through the dictionary as well, but one thing I've found that works much faster is to convert to a panel and then to a dataframe. Say you have a dictionary d
import pandas as pd
d
{'RAY Index': {datetime.date(2014, 11, 3): {'PX_LAST': 1199.46,
'PX_OPEN': 1200.14},
datetime.date(2014, 11, 4): {'PX_LAST': 1195.323, 'PX_OPEN': 1197.69},
datetime.date(2014, 11, 5): {'PX_LAST': 1200.936, 'PX_OPEN': 1195.32},
datetime.date(2014, 11, 6): {'PX_LAST': 1206.061, 'PX_OPEN': 1200.62}},
'SPX Index': {datetime.date(2014, 11, 3): {'PX_LAST': 2017.81,
'PX_OPEN': 2018.21},
datetime.date(2014, 11, 4): {'PX_LAST': 2012.1, 'PX_OPEN': 2015.81},
datetime.date(2014, 11, 5): {'PX_LAST': 2023.57, 'PX_OPEN': 2015.29},
datetime.date(2014, 11, 6): {'PX_LAST': 2031.21, 'PX_OPEN': 2023.33}}}
The command
pd.Panel(d)
<class 'pandas.core.panel.Panel'>
Dimensions: 2 (items) x 2 (major_axis) x 4 (minor_axis)
Items axis: RAY Index to SPX Index
Major_axis axis: PX_LAST to PX_OPEN
Minor_axis axis: 2014-11-03 to 2014-11-06
where pd.Panel(d)[item] yields a dataframe
pd.Panel(d)['SPX Index']
2014-11-03 2014-11-04 2014-11-05 2014-11-06
PX_LAST 2017.81 2012.10 2023.57 2031.21
PX_OPEN 2018.21 2015.81 2015.29 2023.33
You can then hit the command to_frame() to turn it into a dataframe. I use reset_index as well to turn the major and minor axis into columns rather than have them as indices.
pd.Panel(d).to_frame().reset_index()
major minor RAY Index SPX Index
PX_LAST 2014-11-03 1199.460 2017.81
PX_LAST 2014-11-04 1195.323 2012.10
PX_LAST 2014-11-05 1200.936 2023.57
PX_LAST 2014-11-06 1206.061 2031.21
PX_OPEN 2014-11-03 1200.140 2018.21
PX_OPEN 2014-11-04 1197.690 2015.81
PX_OPEN 2014-11-05 1195.320 2015.29
PX_OPEN 2014-11-06 1200.620 2023.33
Finally, if you don't like the way the frame looks you can use the transpose function of panel to change the appearance before calling to_frame() see documentation here http://pandas.pydata.org/pandas-docs/dev/generated/pandas.Panel.transpose.html
Just as an example
pd.Panel(d).transpose(2,0,1).to_frame().reset_index()
major minor 2014-11-03 2014-11-04 2014-11-05 2014-11-06
RAY Index PX_LAST 1199.46 1195.323 1200.936 1206.061
RAY Index PX_OPEN 1200.14 1197.690 1195.320 1200.620
SPX Index PX_LAST 2017.81 2012.100 2023.570 2031.210
SPX Index PX_OPEN 2018.21 2015.810 2015.290 2023.330
Hope this helps.
pd.concat accepts a dictionary. With this in mind, it is possible to improve upon the currently accepted answer in terms of simplicity and performance by use a dictionary comprehension to build a dictionary mapping keys to sub-frames.
pd.concat({k: pd.DataFrame(v).T for k, v in user_dict.items()}, axis=0)
Or,
pd.concat({
k: pd.DataFrame.from_dict(v, 'index') for k, v in user_dict.items()
},
axis=0)
att_1 att_2
12 Category 1 1 whatever
Category 2 23 another
15 Category 1 10 foo
Category 2 30 bar