I\'ve a table, which describes work slices of a business working calendar: (date format is 24 hours format)
PK | STARTDATE | ENDDATE
______________
Here's an example using SQL Server syntax. First it determines the "heads", or rows that have no previous overlapping rows. To determine the last "child" of a "head", it looks for the last row that is smaller than the next "head". Here's the SQL:
; with heads as
(
select row_number() over (order by head.StartDate) as PK
, *
from YourTable head
where not exists
(
select *
from YourTable prev
where prev.StartDate < head.StartDate
and head.StartDate < prev.EndDate
)
)
select row_number() over (order by h.StartDate) as PK
, h.StartDate
, max(yt.EndDate) as EndDate
from heads h
left join
heads nh
on nh.PK = h.PK + 1
left join
YourTable yt
on h.StartDate <= yt.StartDate
and (yt.StartDate < nh.StartDate or nh.StartDate is null)
group by
h.StartDate
Live example at SQL Fiddle.
This is my solution.
IF OBJECT_ID('tempdb..#tblDates') IS NOT NULL
DROP TABLE #tblDates
CREATE TABLE #tblDates (AutoId INT IDENTITY, StartDate DATE, EndDate DATE)
INSERT #tblDates (StartDate, EndDate) SELECT '2014-11-02', '2014-11-08'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-11-07', '2014-11-10'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-11-06', '2014-11-12'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-11-02', '2014-11-15'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-12-10', '2014-12-13'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-12-12', '2014-12-15'
INSERT #tblDates (StartDate, EndDate) SELECT '2014-12-14', '2014-12-16'
-- Optional / Remove the duplicated records of same StartDate and EndDate
DELETE FROM #tblDates WHERE AutoId NOT IN (SELECT MAX(AutoId) FROM #tblDates GROUP BY StartDate, EndDate)
-- Optional / Get only the record with max EndDate grouped by StartDate, Remove Others
DELETE d1
FROM #tblDates d1
JOIN (SELECT x.StartDate, MAX(x.EndDate) MAXEndDate FROM #tblDates x GROUP BY x.StartDate) d2 ON d2.StartDate = d1.StartDate AND d2.MAXEndDate != d1.EndDate
-- Optional / Get only the record with min StartDate grouped by EndDate, Remove Others
DELETE d1
FROM #tblDates d1
JOIN (SELECT x.EndDate, MIN(x.StartDate) MINStartDate FROM #tblDates x GROUP BY x.EndDate) d2 ON d2.EndDate = d1.EndDate AND d2.MINStartDate != d1.StartDate
-- Optional / Remove the overlapping ranges of relevant StartDate and EndDate
DELETE c
FROM #tblDates p
JOIN #tblDates c ON c.AutoId != p.AutoId AND c.StartDate BETWEEN p.StartDate AND p.EndDate AND c.EndDate BETWEEN p.StartDate AND p.EndDate
;WITH Ranges
AS
(
SELECT s.StartDate, s.EndDate
FROM #tblDates s
LEFT JOIN #tblDates a ON a.AutoId != s.AutoId AND s.StartDate BETWEEN a.StartDate AND a.EndDate AND s.StartDate != a.StartDate
WHERE a.AutoId IS NULL
UNION ALL
SELECT r.StartDate, d.EndDate
FROM Ranges r
JOIN #tblDates d ON r.EndDate != d.EndDate AND r.EndDate BETWEEN d.StartDate AND d.EndDate
)
SELECT StartDate, MAX(EndDate) EndDate FROM Ranges GROUP BY StartDate
Based on ErikE response :
IF(object_id('dbo.Periods') is not null)
drop table Periods
go
create table Periods (
StartDate date not null,
EndDate date not null
)
go
insert into Periods(StartDate,EndDate)
select '1980-01-01','1980-01-10' union all
select '1980-01-03','1980-01-07' union all
select '2000-01-01','2000-01-10' union all
select '2000-01-05','2000-01-30' union all
select '2000-01-12','2000-01-20' union all
select '2021-01-01','2021-01-01'
go
; with LeadLag AS (
SELECT
rownum = row_number() OVER( ORDER BY StartDate),
PrevEndDate = Coalesce(Lag(EndDate) OVER (ORDER BY StartDate), Convert(datetime2, '0001-01-01')),
p.*
FROM Periods p
), Dates AS (
SELECT
StartDate = CASE WHEN PrevEndDate < StartDate THEN StartDate ELSE NULL END,
EndDate,
rownum
FROM LeadLag
), startGrouping AS (
SELECT
StartDate = max(StartDate) OVER (ORDER BY rownum rows UNBOUNDED PRECEDING),
EndDate,
rownum
FROM Dates
),
groups AS (
SELECT
StartDate,
EndDate,
rownum,
ingroupRownum = row_number() OVER(PARTITION BY StartDate ORDER BY EndDate desc)
FROM startGrouping e1
)
SELECT StartDate, EndDate
from groups
WHERE ingroupRownum = 1