Downloading a picture via urllib and python

Question

So I\'m trying to make a Python script that downloads webcomics and puts them in a folder on my desktop. I\'ve found a few similar programs on here that do something simila

Answer 1

Maybe you need 'User-Agent':

import urllib2
opener = urllib2.build_opener()
opener.addheaders = [('User-Agent', 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/34.0.1847.137 Safari/537.36')]
response = opener.open('http://google.com')
htmlData = response.read()
f = open('file.txt','w')
f.write(htmlData )
f.close()

Answer 2

Using urllib, you can get this done instantly.

import urllib.request

opener=urllib.request.build_opener()
opener.addheaders=[('User-Agent','Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/36.0.1941.0 Safari/537.36')]
urllib.request.install_opener(opener)

urllib.request.urlretrieve(URL, "images/0.jpg")

Answer 3

Just for the record, using requests library.

import requests
f = open('00000001.jpg','wb')
f.write(requests.get('http://www.gunnerkrigg.com//comics/00000001.jpg').content)
f.close()

Though it should check for requests.get() error.

Answer 4

Python 2

Using urllib.urlretrieve

import urllib
urllib.urlretrieve("http://www.gunnerkrigg.com//comics/00000001.jpg", "00000001.jpg")

Python 3

Using urllib.request.urlretrieve (part of Python 3's legacy interface, works exactly the same)

import urllib.request
urllib.request.urlretrieve("http://www.gunnerkrigg.com//comics/00000001.jpg", "00000001.jpg")

Answer 5

This worked for me using python 3.

It gets a list of URLs from the csv file and starts downloading them into a folder. In case the content or image does not exist it takes that exception and continues making its magic.

import urllib.request
import csv
import os

errorCount=0

file_list = "/Users/$USER/Desktop/YOUR-FILE-TO-DOWNLOAD-IMAGES/image_{0}.jpg"

# CSV file must separate by commas
# urls.csv is set to your current working directory make sure your cd into or add the corresponding path
with open ('urls.csv') as images:
    images = csv.reader(images)
    img_count = 1
    print("Please Wait.. it will take some time")
    for image in images:
        try:
            urllib.request.urlretrieve(image[0],
            file_list.format(img_count))
            img_count += 1
        except IOError:
            errorCount+=1
            # Stop in case you reach 100 errors downloading images
            if errorCount>100:
                break
            else:
                print ("File does not exist")

print ("Done!")

Answer 6

For Python 3 you will need to import import urllib.request:

import urllib.request 

urllib.request.urlretrieve(url, filename)

for more info check out the link