Downloading a picture via urllib and python

Question

So I\'m trying to make a Python script that downloads webcomics and puts them in a folder on my desktop. I\'ve found a few similar programs on here that do something simila

Answer 1

It's easiest to just use .read() to read the partial or entire response, then write it into a file you've opened in a known good location.

Answer 2

I have found this answer and I edit that in more reliable way

def download_photo(self, img_url, filename):
    try:
        image_on_web = urllib.urlopen(img_url)
        if image_on_web.headers.maintype == 'image':
            buf = image_on_web.read()
            path = os.getcwd() + DOWNLOADED_IMAGE_PATH
            file_path = "%s%s" % (path, filename)
            downloaded_image = file(file_path, "wb")
            downloaded_image.write(buf)
            downloaded_image.close()
            image_on_web.close()
        else:
            return False    
    except:
        return False
    return True

From this you never get any other resources or exceptions while downloading.

Answer 3

Aside from suggesting you read the docs for retrieve() carefully (http://docs.python.org/library/urllib.html#urllib.URLopener.retrieve), I would suggest actually calling read() on the content of the response, and then saving it into a file of your choosing rather than leaving it in the temporary file that retrieve creates.

Answer 4

Python 3 version of @DiGMi's answer:

from urllib import request
f = open('00000001.jpg', 'wb')
f.write(request.urlopen("http://www.gunnerkrigg.com/comics/00000001.jpg").read())
f.close()

Answer 5

What about this:

import urllib, os

def from_url( url, filename = None ):
    '''Store the url content to filename'''
    if not filename:
        filename = os.path.basename( os.path.realpath(url) )

    req = urllib.request.Request( url )
    try:
        response = urllib.request.urlopen( req )
    except urllib.error.URLError as e:
        if hasattr( e, 'reason' ):
            print( 'Fail in reaching the server -> ', e.reason )
            return False
        elif hasattr( e, 'code' ):
            print( 'The server couldn\'t fulfill the request -> ', e.code )
            return False
    else:
        with open( filename, 'wb' ) as fo:
            fo.write( response.read() )
            print( 'Url saved as %s' % filename )
        return True

##

def main():
    test_url = 'http://cdn.sstatic.net/stackoverflow/img/favicon.ico'

    from_url( test_url )

if __name__ == '__main__':
    main()

Answer 6

A simpler solution may be(python 3):

import urllib.request
import os
os.chdir("D:\\comic") #your path
i=1;
s="00000000"
while i<1000:
    try:
        urllib.request.urlretrieve("http://www.gunnerkrigg.com//comics/"+ s[:8-len(str(i))]+ str(i)+".jpg",str(i)+".jpg")
    except:
        print("not possible" + str(i))
    i+=1;