How to invoke pointer to member function when it's a class data member?

Question

struct B
{
  void (B::*pf)(int, int);  // data member
  B () : pf(&B::foo) {}
  void foo (int i, int j) { cout<<\"foo(int, int)\\n\"; } // target method
};         


        

Answer 1

Like this:

(obj.*obj.pf)(0, 1);

Member access (.) has a higher precedence than a pointer to member operator so this is equivalent to:

(obj.*(obj.pf))(0, 1);

Because function call also has higher precedence than a pointer to member operator, you can't do:

obj.*obj.pf(0, 1) /* or */ obj.*(obj.pf)(0, 1)

As that would be equivalent to:

obj.*(obj.pf(0, 1)) // grammar expects obj.pf to be a callable returning a
                    // pointer to member

Answer 2

The syntax is quite unnatural but a consequence of C++ precedence rules...

(obj.*obj.pf)(1, 2);

Answer 3

pf is a method pointer, and you want to invoke the method it points to, so you have to use

(obj.*obj.pf)(1, 2);

It says the object obj you invoke the method pointed by pf

See result here :

http://ideone.com/p3a5G