How to call a php function from ajax?

Question

I am familiar of how to get ajax to go to a php page an execute a series of things and then return json data. However is it possible to call a specific function which reside

Answer 1

    $(document).ready(function(){
            $('#tfa_1117700').change(function(){
                var inputValue = $(this).val();
                var v_token = "{{csrf_token()}}";
                $.post("{{url('/each-child')}}", { dropdownValue: inputValue,_token:v_token }, function(data){
                    console.log(data);
                    $('#each-child-html').html(data);
                });
            });
        });



 public function EachChild(Request $request){
            $html ="";
            for ($i=1; $i <= $request->dropdownValue; $i++) { 
                $html = $i;
            }
            echo $html;

        }

Answer 2

You can't call a PHP function directly from an AJAX call, but you can do this:

<? php 
    function test($data){
        return $data+1;
    }

    if (isset($_POST['callFunc1'])) {
        echo test($_POST['callFunc1']);
    }
?>
<script>
    $.ajax({
        url: 'myFunctions.php',
        type: 'post',
        data: { "callFunc1": "1"},
        success: function(response) { console.log(response); }
    });
</script>

Answer 3

If I understand correctly, yes you can. Put all your functions in one php file and have the ajax pass as a parameter which one you want to call. Then with a switch or if structure, execute the one you want.

Answer 4

For AJAX request

1. Include jQuery Library in your web page. For e.g.

   <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
   

2. Call a function on button click

   <button type="button" onclick="create()">Click Me</button>
   

3. While click on button, call create function in JavaScript.

   <script>
       function create () {
           $.ajax({
               url:"test.php",    //the page containing php script
               type: "post",    //request type,
               dataType: 'json',
               data: {registration: "success", name: "xyz", email: "abc@gmail.com"},
               success:function(result){
                   console.log(result.abc);
               }
           });
       }
   </script>
   

On the server side test.php file, the action POST parameter should be read and the corresponding value and do the action in PHP and return in JSON format e.g.

$registration = $_POST['registration'];
$name= $_POST['name'];
$email= $_POST['email'];

if ($registration == "success"){
    // some action goes here under php
    echo json_encode(array("abc"=>'successfuly registered'));
}