I am having some seemingly trivial trouble with numpy when the array contains string data. I have the following code:
my_array = numpy.empty([1, 2], dty
Numpy requires string arrays to have a fixed maximum length. When you create an empty array with dtype=str
, it sets this maximum length to 1 by default. You can see if you do my_array.dtype
; it will show "|S1", meaning "one-character string". Subsequent assignments into the array are truncated to fit this structure.
You can pass an explicit datatype with your maximum length by doing, e.g.:
my_array = numpy.empty([1, 2], dtype="S10")
The "S10" will create an array of length-10 strings. You have to decide how big will be big enough to hold all the data you want to hold.
I got a "codec error" when I tried to use a non-ascii character with dtype="S10"
You also get an array with binary strings, which confused me.
I think it is better to use:
my_array = numpy.empty([1, 2], dtype="<U10")
Here 'U10' translates to "Unicode string of length 10; little endian format"
The numpy string array is limited by its fixed length (length 1 by default). If you're unsure what length you'll need for your strings in advance, you can use dtype=object
and get arbitrary length strings for your data elements:
my_array = numpy.empty([1, 2], dtype=object)
I understand there may be efficiency drawbacks to this approach, but I don't have a good reference to support that.
Another alternative is to initialize as follows:
my_array = np.array([["CAT","APPLE"],['','']], dtype=str)
In other words, first you write a regular array with what you want, then you turn it into a numpy array. However, this will fix your max string length to the length of the longest string at initialization. So if you were to add
my_array[1,0] = 'PINEAPPLE'
then the string stored would be 'PINEA'.
What works best if you are doing a for loop is to start a list comprehension, which will allow you to allocate the right memory.
data = ['CAT','APPLE,'CARROT']
my_array = [name for name in data]