Removing elements that have consecutive duplicates

Question

I was curios about the question: Eliminate consecutive duplicates of list elements, and how it should be implemented in Python.

What I came up with is this:

Answer 1

Plenty of better/more pythonic answers above, however one could also accomplish this task using list.pop():

my_list = [1, 2, 3, 3, 4, 3, 5, 5]
for x in my_list[:-1]:
    next_index = my_list.index(x) + 1
    if my_list[next_index] == x:
        my_list.pop(next_index)

outputs

[1, 2, 3, 4, 3, 5]

Answer 2

Oneliner in pure Python

[v for i, v in enumerate(your_list) if i == 0 or v != your_list[i-1]]

Answer 3

>>> L = [1,1,1,1,1,1,2,3,4,4,5,1,2]
>>> from itertools import groupby
>>> [x[0] for x in groupby(L)]
[1, 2, 3, 4, 5, 1, 2]

If you wish, you can use map instead of the list comprehension

>>> from operator import itemgetter
>>> map(itemgetter(0), groupby(L))
[1, 2, 3, 4, 5, 1, 2]

For the second part

>>> [x for x, y in groupby(L) if len(list(y)) < 2]
[2, 3, 5, 1, 2]

If you don't want to create the temporary list just to take the length, you can use sum over a generator expression

>>> [x for x, y in groupby(L) if sum(1 for i in y) < 2]
[2, 3, 5, 1, 2]

Answer 4

To Eliminate consecutive duplicates of list elements; as an alternative, you may use itertools.zip_longest() with list comprehension as:

>>> from itertools import zip_longest

>>> my_list = [1,1,1,1,1,1,2,3,4,4,5,1,2]
>>> [i for i, j in zip_longest(my_list, my_list[1:]) if i!=j]
[1, 2, 3, 4, 5, 1, 2]

Answer 5

Here is a solution without dependence on outside packages:

list = [1,1,1,1,1,1,2,3,4,4,5,1,2] 
L = list + [999]  # append a unique dummy element to properly handle -1 index
[l for i, l in enumerate(L) if l != L[i - 1]][:-1] # drop the dummy element

Then I noted that Ulf Aslak's similar solution is cleaner :)

Answer 6

You can do this by using zip_longest() + list comprehension.

from itertools import zip_longest 
list1 = [1, 2, 3, 3, 4, 3, 5, 5].
     # using zip_longest()+ list comprehension       
     res = [i for i, j in zip_longest(list1, list1[1:]) 
                                                            if i != j] 
        print ("List after removing consecutive duplicates : " +  str(res))