How to check for palindrome using Python logic [closed]

Answer 1

def pali(str1):
    l=list(str1)
    l1=l[::-1]
    if l1==l:
        print("yess")
    else:
        print("noo")
str1="abc"
a=pali(str1)
print(a)

Answer 2

Here is an example that takes a user's input and checks if the input is a palindrome:

name = input("Write your word here:  ")
input("Press <enter> to check if the word is a palindrome.")
if str(name) == str(name)[::-1]:
    print("True")
else:
    print("False")

However, there is no need to even set up the if/else statement. You can directly print the result of the logical comparison, as shown here:

name = input("Write your word here:  ")
input("Press <enter> to check if the word is a palindrome.")
print(str(name) == str(name)[::-1])

Answer 3

The awesome part of python is the things you can do with it. You don't have to use indexes for strings.

The following will work (using slices)

def palindrome(n):
    return n == n[::-1]

What it does is simply reverses n, and checks if they are equal. n[::-1] reverses n (the -1 means to decrement)

"2) My for loop (in in range (999, 100, -1), is this a bad way to do it in Python?"

Regarding the above, you want to use xrange instead of range (because range will create an actual list, while xrange is a fast generator)

My opinions on question 3

I learned C before Python, and I just read the docs, and played around with it using the console. (and by doing Project Euler problems as well :)

Answer 4

There is much easier way I just found. It's only 1 line.

is_palindrome = word.find(word[::-1])

Answer 5

Here a case insensitive function since all those solutions above are case sensitive.

def Palindrome(string): 

  return (string.upper() == string.upper()[::-1]) 

This function will return a boolean value.

Answer 6

It looks prettier with recursion!

def isPalindrome(x):
z = numToList(x)
length = math.floor(len(z) / 2)
if length < 2:
    if z[0] == z[-1]:
        return True
    else:
        return False
else:
    if z[0] == z[-1]:
        del z[0]
        del z[-1]
        return isPalindrome(z)
    else:
        return False