How to ignore the first line of data when processing CSV data?

Question

I am asking Python to print the minimum number from a column of CSV data, but the top row is the column number, and I don\'t want Python to take the top row into account. Ho

Answer 1

Borrowed from python cookbook,
A more concise template code might look like this:

import csv
with open('stocks.csv') as f:
    f_csv = csv.reader(f) 
    headers = next(f_csv) 
    for row in f_csv:
        # Process row ...

Answer 2

Python 2.x

csvreader.next()

Return the next row of the reader’s iterable object as a list, parsed according to the current dialect.

csv_data = csv.reader(open('sample.csv'))
csv_data.next() # skip first row
for row in csv_data:
    print(row) # should print second row

---

Python 3.x

csvreader.__next__()

Return the next row of the reader’s iterable object as a list (if the object was returned from reader()) or a dict (if it is a DictReader instance), parsed according to the current dialect. Usually you should call this as next(reader).

csv_data = csv.reader(open('sample.csv'))
csv_data.__next__() # skip first row
for row in csv_data:
    print(row) # should print second row

Answer 3

Python 3.X

Handles UTF8 BOM + HEADER

It was quite frustrating that the csv module could not easily get the header, there is also a bug with the UTF-8 BOM (first char in file). This works for me using only the csv module:

import csv

def read_csv(self, csv_path, delimiter):
    with open(csv_path, newline='', encoding='utf-8') as f:
        # https://bugs.python.org/issue7185
        # Remove UTF8 BOM.
        txt = f.read()[1:]

    # Remove header line.
    header = txt.splitlines()[:1]
    lines = txt.splitlines()[1:]

    # Convert to list.
    csv_rows = list(csv.reader(lines, delimiter=delimiter))

    for row in csv_rows:
        value = row[INDEX_HERE]

Answer 4

To skip the first line just call:

next(inf)

Files in Python are iterators over lines.

Answer 5

this might be a very old question but with pandas we have a very easy solution

import pandas as pd

data=pd.read_csv('all16.csv',skiprows=1)
data['column'].min()

with skiprows=1 we can skip the first row then we can find the least value using data['column'].min()

Answer 6

The documentation for the Python 3 CSV module provides this example:

with open('example.csv', newline='') as csvfile:
    dialect = csv.Sniffer().sniff(csvfile.read(1024))
    csvfile.seek(0)
    reader = csv.reader(csvfile, dialect)
    # ... process CSV file contents here ...

The Sniffer will try to auto-detect many things about the CSV file. You need to explicitly call its has_header() method to determine whether the file has a header line. If it does, then skip the first row when iterating the CSV rows. You can do it like this:

if sniffer.has_header():
    for header_row in reader:
        break
for data_row in reader:
    # do something with the row