How to use jQuery for XML parsing with namespaces

Question

I\'m new to jQuery and would like to parse an XML document.

I\'m able to parse regular XML with the default namespaces but with XML such as:

Answer 1

content: $this.find("content\\:encoded, encoded").text()

is the perfect solution...

Answer 2

just replaced the namespace by empty string. Works fine for me. Tested solution across browsers: Firefox, IE, Chrome

My task was to read and parse an EXCEL-file via Sharepoint EXCEL REST API. The XML-response contains tags with "x:" namespace.

I decided to replace the namespace in the XML by an empty string. Works this way: 1. Get the node of interest out of the XML-response 2. Convert the selected node XML-Response (Document) to String 2. Replace namespace by empty string 3. Convert string back to XML-Document

See code outline here -->

function processXMLResponse)(xData)
{
  var xml = TOOLS.convertXMLToString("", "",$(xData).find("entry content")[0]);
  xml = xml.replace(/x:/g, "");            // replace all occurences of namespace
  xData =  TOOLS.createXMLDocument(xml);   // convert string back to XML
}

For XML-to-String conversion find a solution here: http://www.sencha.com/forum/showthread.php?34553-Convert-DOM-XML-Document-to-string

Answer 3

I have spent several hours on this reading about plugins and all sorts of solutions with no luck.

ArnisAndy posted a link to a jQuery discussion, where this answer is offered and I can confirm that this works for me in Chrome(v18.0), FireFox(v11.0), IE(v9.08) and Safari (v5.1.5) using jQuery (v1.7.2).

I am trying to scrape a WordPress feed where content is named <content:encoded> and this is what worked for me:

content: $this.find("content\\:encoded, encoded").text()

Answer 4

If you are using jquery 1.5 you will have to add quotes around the node selector attribute value to make it work:

.find('[nodeName="z:row"]')

Answer 5

None of the solutions above work that well. I found this and has been improved for speed. just add this, worked like a charm:

$.fn.filterNode = function(name) {
    return this.find('*').filter(function() {
       return this.nodeName === name;
    });
};

usage:

var ineedthatelementwiththepsuedo = $('someparentelement').filterNode('dc:creator');

source: http://www.steveworkman.com/html5-2/javascript/2011/improving-javascript-xml-node-finding-performance-by-2000/

Answer 6

Original Answer : jQuery XML parsing how to get element attribute

Here is an example for how to successfully get the value in Chrome..

 item.description = jQuery(this).find("[nodeName=itunes\\:summary]").eq(0).text();