Is there a way to make a form that has no border (FormBorderStyle is set to \"none\") movable when the mouse is clicked down on the form just as if there was a border?
I'm expanding the solution from jay_t55 with one more method ToolStrip1_MouseLeave
that handles the event of the mouse moving quickly and leaving the region.
private bool mouseDown;
private Point lastLocation;
private void ToolStrip1_MouseDown(object sender, MouseEventArgs e) {
mouseDown = true;
lastLocation = e.Location;
}
private void ToolStrip1_MouseMove(object sender, MouseEventArgs e) {
if (mouseDown) {
this.Location = new Point(
(this.Location.X - lastLocation.X) + e.X, (this.Location.Y - lastLocation.Y) + e.Y);
this.Update();
}
}
private void ToolStrip1_MouseUp(object sender, MouseEventArgs e) {
mouseDown = false;
}
private void ToolStrip1_MouseLeave(object sender, EventArgs e) {
mouseDown = false;
}
Let's not make things any more difficult than they need to be. I've come across so many snippets of code that allow you to drag a form around (or another Control). And many of them have their own drawbacks/side effects. Especially those ones where they trick Windows into thinking that a Control on a form is the actual form.
That being said, here is my snippet. I use it all the time. I'd also like to note that you should not use this.Invalidate(); as others like to do because it causes the form to flicker in some cases. And in some cases so does this.Refresh. Using this.Update, I have not had any flickering issues:
private bool mouseDown;
private Point lastLocation;
private void Form1_MouseDown(object sender, MouseEventArgs e)
{
mouseDown = true;
lastLocation = e.Location;
}
private void Form1_MouseMove(object sender, MouseEventArgs e)
{
if(mouseDown)
{
this.Location = new Point(
(this.Location.X - lastLocation.X) + e.X, (this.Location.Y - lastLocation.Y) + e.Y);
this.Update();
}
}
private void Form1_MouseUp(object sender, MouseEventArgs e)
{
mouseDown = false;
}
https://social.msdn.microsoft.com/Forums/vstudio/en-US/d803d869-68e6-46ff-9ff1-fabf78d6393c/how-to-make-a-borderless-form-in-c?forum=csharpgeneral
This bit of code from the above link did the trick in my case :)
protected override void OnMouseDown(MouseEventArgs e)
{
base.OnMouseDown(e);
if (e.Button == MouseButtons.Left)
{
this.Capture = false;
Message msg = Message.Create(this.Handle, 0XA1, new IntPtr(2), IntPtr.Zero);
this.WndProc(ref msg);
}
}
For .NET Framework 4,
You can use this.DragMove()
for the MouseDown
event of the component (mainLayout in this example) you are using to drag.
private void mainLayout_MouseDown(object sender, MouseButtonEventArgs e)
{
this.DragMove();
}
There's no property you can flip to make this just happen magically. Look at the events for the form and it becomes fairly trivial to implement this by setting this.Top
and this.Left
. Specifically you'll want to look at MouseDown
, MouseUp
and MouseMove
.
Since some answers do not allow for child controls to be draggable, I've created a little helper class. It should be passed the top level form. Can be made more generic if desired.
class MouseDragger
{
private readonly Form _form;
private Point _mouseDown;
protected void OnMouseDown(object sender, MouseEventArgs e)
{
_mouseDown = e.Location;
}
protected void OnMouseMove(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
int dx = e.Location.X - _mouseDown.X;
int dy = e.Location.Y - _mouseDown.Y;
_form.Location = new Point(_form.Location.X + dx, _form.Location.Y + dy);
}
}
public MouseDragger(Form form)
{
_form = form;
MakeDraggable(_form);
}
private void MakeDraggable(Control control)
{
var type = control.GetType();
if (typeof(Button).IsAssignableFrom(type))
{
return;
}
control.MouseDown += OnMouseDown;
control.MouseMove += OnMouseMove;
foreach (Control child in control.Controls)
{
MakeDraggable(child);
}
}
}