I have an application where on the home page I have buttons for navigation through the application.
On that page I have a button \"EXIT\" which when clicked should t
Here's what i did:
SomeActivity.java
@Override
public void onBackPressed() {
Intent newIntent = new Intent(this,QuitAppActivity.class);
newIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP|Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(newIntent);
finish();
}
QuitAppActivity.java
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
finish();
}
Basically what you did is cleared all activities from the stack and launch QuitAppActivity
, that will finish the task.
There is another option, to use the FinishAffinity method to close all the tasks in the stack related to the app.
See: https://stackoverflow.com/a/27765687/1984636
I tried exiting application using following code snippet, this it worked for me. Hope this helps you. i did small demo with 2 activities
first activity
public class MainActivity extends Activity implements OnClickListener{
private Button secondActivityBtn;
private SharedPreferences pref;
private SharedPreferences.Editor editer;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
secondActivityBtn=(Button) findViewById(R.id.SecondActivityBtn);
secondActivityBtn.setOnClickListener(this);
pref = this.getSharedPreferences("MyPrefsFile", MODE_PRIVATE);
editer = pref.edit();
if(pref.getInt("exitApp", 0) == 1){
editer.putInt("exitApp", 0);
editer.commit();
finish();
}
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.SecondActivityBtn:
Intent intent= new Intent(MainActivity.this, YourAnyActivity.class);
startActivity(intent);
break;
default:
break;
}
}
}
your any other activity
public class YourAnyActivity extends Activity implements OnClickListener {
private Button exitAppBtn;
private SharedPreferences pref;
private SharedPreferences.Editor editer;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_any);
exitAppBtn = (Button) findViewById(R.id.exitAppBtn);
exitAppBtn.setOnClickListener(this);
pref = this.getSharedPreferences("MyPrefsFile", MODE_PRIVATE);
editer = pref.edit();
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.exitAppBtn:
Intent main_intent = new Intent(YourAnyActivity.this,
MainActivity.class);
main_intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(main_intent);
editer.putInt("exitApp",1);
editer.commit();
break;
default:
break;
}
}
}
Android's design does not favor exiting an application by choice, but rather manages it by the OS. You can bring up the Home application by its corresponding Intent:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.addCategory(Intent.CATEGORY_HOME);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
When u call finish onDestroy() of that activity will be called and it will go back to previous activity in the activity stack... So.. for exit do not call finish();
(I tried previous answers but they lacks in some points. For example if you don't do a return;
after finishing activity, remaining activity code runs. Also you need to edit onCreate with return. If you doesn't run super.onCreate() you will get a runtime error)
Say you have MainActivity
and ChildActivity
.
Inside ChildActivity add this:
Intent intent = new Intent(ChildActivity.this, MainActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
intent.putExtra("EXIT", true);
startActivity(intent);
return true;
Inside MainActivity's onCreate add this:
@Override
public void onCreate(Bundle savedInstanceState) {
mContext = getApplicationContext();
super.onCreate(savedInstanceState);
if (getIntent().getBooleanExtra("EXIT", false)) {
finish();
return;
}
// your current codes
// your current codes
}