Python: finding lowest integer

Question

I have the following code:

l = [\'-1.2\', \'0.0\', \'1\']

x = 100.0
for i in l:
    if i < x:
        x = i
print x

The code should fin

Answer 1

number_list = [99.5,1.2,-0.3]

number_list.sort()

print number_list[0]

Answer 2

It looks like you want to convert the list to a list of numbers

>>> foo = ['-1.2', '0.0', '1']
>>> bar = map(float, foo)
>>> bar
[-1.2, 0.0, 1.0]
>>> min(bar)
-1.2

or if it really is strings you want, that you want to use min's key argument

>>> foo = ['-1.2', '0.0', '1']
>>> min(foo, key=float)
'-1.2'

Answer 3

Or no float conversion at all by just specifying floats in the list.

l = [-1.2, 0.0, 1]
x = min(l)

or

l = min([-1.2, 0.0, 1])

Answer 4

You have to start somewhere the correct code should be:

The code to return the minimum value

l = [ '0.0', '1','-1.2'] x = l[0] for i in l: if i < x: x = i print x

But again it's good to use directly integers instead of using quotations ''

This way!

l = [ 0.0, 1,-1.2] x = l[0] for i in l: if i < x: x = i print x

Answer 5

list1 = [10,-4,5,2,33,4,7,8,2,3,5,8,99,-34]

print(list1)

max_v=list1[0]

min_v=list1[0]

for x in list1:
    if x>max_v:
        max_v=x
        print('X is {0} and max is {1}'.format(x,max_v))
for x in list1:
    if x<min_v:
        min_v=x
        print('X is {0} and min is {1}'.format(x,min_v))

print('Max values is ' + str(max_v))
print('Min values is ' + str(min_v))

Answer 6

You have strings in the list and you are comparing them with the number 100.0.