I am using the following regex to match a URL:
$search = \"/([\\S]+\\.(MUSEUM|TRAVEL|AERO|ARPA|ASIA|COOP|INFO|NAME|BIZ|CAT|COM|INT|JOBS|NET|ORG|PRO|TEL|AC|A
Try Regexy::Web::Url
r = Regexy::Web::Url.new # matches 'http://foo.com', 'www.foo.com' and 'foo.com'
$search = "#^((?#
the scheme:
)(?:https?://)(?#
second level domains and beyond:
)(?:[\S]+\.)+((?#
top level domains:
)MUSEUM|TRAVEL|AERO|ARPA|ASIA|EDU|GOV|MIL|MOBI|(?#
)COOP|INFO|NAME|BIZ|CAT|COM|INT|JOBS|NET|ORG|PRO|TEL|(?#
)A[CDEFGILMNOQRSTUWXZ]|B[ABDEFGHIJLMNORSTVWYZ]|(?#
)C[ACDFGHIKLMNORUVXYZ]|D[EJKMOZ]|(?#
)E[CEGHRSTU]|F[IJKMOR]|G[ABDEFGHILMNPQRSTUWY]|(?#
)H[KMNRTU]|I[DELMNOQRST]|J[EMOP]|(?#
)K[EGHIMNPRWYZ]|L[ABCIKRSTUVY]|M[ACDEFGHKLMNOPQRSTUVWXYZ]|(?#
)N[ACEFGILOPRUZ]|OM|P[AEFGHKLMNRSTWY]|QA|R[EOSUW]|(?#
)S[ABCDEGHIJKLMNORTUVYZ]|T[CDFGHJKLMNOPRTVWZ]|(?#
)U[AGKMSYZ]|V[ACEGINU]|W[FS]|Y[ETU]|Z[AMW])(?#
the path, can be there or not:
)(/[a-z0-9\._/~%\-\+&\#\?!=\(\)@]*)?)$#i";
Just cleaned up a bit. This will match only HTTP(s) addresses, and, as long as you copied all top level domains correctly from IANA, only those standardized (it will not match http://localhost
) and with the http://
declared.
Finally you should end with the path part, that will always start with a /, if it is there.
However, I'd suggest to follow Cerebrus: If you're not sure about this, learn regexps in a more gentle way and use proven patterns for complicated tasks.
Cheers,
By the way: Your regexp will also match something.r
and something.h
(between |TO| and |TR| in your example). I left them out in my version, as I guess it was a typo.
On re-reading the question: Change
)(?:https?://)(?#
to
)(?:https?://)?(?#
(there is a ?
extra) to match 'URLs' without the scheme.
$ : The dollar signifies the end of the string.
For example \d*$ will match strings which end with a digit.
So you need to add the $!
This question was surprisingly difficult to find an answer for. The regexes I found were too complicated to understand, and anything more that a regex is overkill and too difficult to implement.
Finally came up with:
/(\S+\.(com|net|org|edu|gov)(\/\S+)?)/
Works with http://example.com
, https://example.com
, example.com
, http://example.com/foo
.
Explanation:
Changing the end of the regex to (/\S*)?)$
should solve your problem.
To explain what that is doing -
/
followed by some characters (not whitespace) ?
indicated 0 or 1 times \b
for matching on a word boundary).Just to add to things. I know this doesn't fully and directly answer this specific question, but it's the best place I can find to add this info. I wrote a jQuery plug a while back to match urls for similar purpose, however at current state (will update it as time goes on) it will still consider addresses like 'http://abc.php' as valid. However, if there is no http, https, or ftp at url start, it will not return 'valid'. Though I should clarify, this jQuery method returns an object and not just one string or boolean. The object breaks things down and among the breakdown is a .valid boolean. See the full fiddle and test in the link at bottom. If you simply wanna grab the plugin and go, see below:
jQuery Plugin
(function($){$.matchUrl||$.extend({matchUrl:function(c){var b=void 0,d="url,,scheme,,authority,path,,query,,fragment".split(","),e=/^(([^\:\/\?\#]+)\:)?(\/\/([^\/\?\#]*))?([^\?\#]*)(\?([^\#]*))?(\#(.*))?/,a={url:void 0,scheme:void 0,authority:void 0,path:void 0,query:void 0,fragment:void 0,valid:!1};"string"===typeof c&&""!=c&&(b=c.match(e));if("object"===typeof b)for(x in b)d[x]&&""!=d[x]&&(a[d[x]]=b[x]);a.scheme&&a.authority&&(a.valid=!0);return a}});})(jQuery);
jsFiddle with example:
http://jsfiddle.net/SpYk3/e4Ank/