I’v come across both ways to apply Array prototypes to a native object:
arr = Array.prototype.slice.call(obj);
arr = [].slice.call(obj);
In
That's an interesting question! Let's pull up the pros (✔️) and cons (❌) for each alternative:
[].slice
[.slice
is a typo.slice
) faster.Contrary to what you'd think and read pretty much everywhere, [].slice.call(...)
does NOT instantiate a new, empty Array
just to access its slice
property!.
Nowadays (it has been so for 5+ years – as of late 2018), the JIT compilation (1) is included everywhere you run JavaScript (unless you're still browsing the Web with IE8 or lower).
This mechanism allows the JS Engine to: (2)
... resolve
[].slice
directly, and statically, as directArray.prototype
reference in one shot, and just one configurable property access:forEach
Array.prototype.slice
Array.prorotype.slice
) look fine until you try and run the code.❌: Runs slower
Array.prototype.slice
is: (2)
... a lookup for the whole scope for an
Array
reference until all scopes are walked 'till the global one ... because you can name a variableArray
any time you want.Once the global scope is reached, and the native found, the engine accesses its proottype and after that its method
...
O(N) scope resolution + 2 properties access (.prototype
and.forEach
).
✔️: Allows you to seamlessly adapt to whichever coding conventions would strictly prevent you from having a line start with either (
, [
or `
Definitely a good thing.
[].slice
is better in pretty much every wayThey are identical regarding functionality.
However, the Array
object can be overwritten, causing the first method to fail.
//Example:
Array = {};
console.log(typeof Array.prototype.slice); // "undefined"
console.log(typeof [].slice); // "function"
The literal method creates a new instance of Array
(opposed to Array.prototype.
method). Benchmark of both methods: http://jsperf.com/bbarr-new-array-vs-literal/3
When you're going to use the method many times, the best practice is to cache the method:
var slice = Array.prototype.slice; //Commonly used
var slice = [].slice;
- If you're concerned about the existence of Array
, or if you just like the shorter syntax.