How can I compare two dates, return a number of days

Question

how can I compare two dates return number of days. Ex: Missing X days of the Cup. look my code.

  NSDateFormatter *df = [[NSDateFormatter alloc]init];  
  [d         


        

Answer 1

From Apple's example, basically use an NSCalendar:

NSDate * date1 = <however you initialize this>;
NSDate * date2 = <...>;

NSCalendar *gregorian = [[NSCalendar alloc]
                 initWithCalendarIdentifier:NSGregorianCalendar];

NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit;

NSDateComponents *components = [gregorian components:unitFlags
                                          fromDate:date1
                                          toDate:date2 options:0];

NSInteger months = [components month];
NSInteger days = [components day];

Answer 2

Need to call this method and set 2 dates only which we want to calculate differently.

-(void) calculateSleepHours:(NSDate *)sleepDate :(NSDate *)wakeStr 
{

   if (sleepDate !=nil && wakeStr!=nil) {`enter code here`

    NSDateFormatter *dateFormatter1 = [[NSDateFormatter alloc] init];
    [dateFormatter1 setDateFormat:@"yyyy-MM-dd HH:mm:ssZ"];
    NSDate *date1 = [ApplicationManager getInstance].sleepTime;;

    NSDate *date2 = [ApplicationManager getInstance].wakeupTime;

    NSCalendar *gregorian = [[NSCalendar alloc]
                             initWithCalendarIdentifier:NSGregorianCalendar];

    NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit|NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit;

    NSDateComponents *components = [gregorian components:unitFlags
                                                fromDate:date1
                                                  toDate:date2 options:0];

    NSInteger months = [components month];
    NSInteger days = [components day];
    NSInteger hours = [components hour];
    NSInteger minute=[components minute];
    NSInteger second=[components second];
    DLog(@"Month %ld day %ld hour is %ld min %ld sec %ld  ",(long)months,(long)days,(long)hours,(long)minute,(long)second);

    sleepHours.text=[NSString stringWithFormat:@"Hour %ld Min %ld Sec %ld",(long)hours,(long)minute,(long)second];
    }
}

Answer 3

You can use next category:

@interface NSDate (Additions)

-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate; 
-(NSInteger)numberOfHoursUntilDay:(NSDate *)aDate;

@end

@implementation NSDate (Additions)
const NSInteger secondPerMunite = 60;       
const NSInteger munitePerHour = 60;
const NSInteger hourPerDay = 24;

-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate 
{
    NSInteger selfTimeInterval = [aDate timeIntervalSinceDate:self];   
    return abs(selfTimeInterval / (secondPerMunite * munitePerHour * hourPerDay));    
}

-(NSInteger)numberOfHoursUntilDay:(NSDate *)aDate 
{
    NSInteger selfTimeInterval = [aDate timeIntervalSinceDate:self];
    return abs(selfTimeInterval / (secondPerMunite * munitePerHour));
}
@end

Answer 4

Try this category:

@interface NSDate (DateUtils)

-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate; 

@end

@implementation NSDate (DateUtils)

-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate
{

    NSCalendar *calendar = [[NSCalendar alloc]
                             initWithCalendarIdentifier:NSCalendarIdentifierGregorian];

    NSDateComponents *components = [calendar components:NSCalendarUnitDay
                                                fromDate:self
                                                  toDate:aDate options:kNilOptions];

    return [components day];

}

@end

You can use this category by adding an import:

#import "NSDate+DateUtils.h"

And call it from your code:

NSInteger days = [myDate numberOfDaysUntilDay:someOtherDate];