I want to create a list (or set) of all unique values appearing in a list of lists in python. I have something like this:
aList=[[\'a\',\'b\'], [\'a\', \'b\'
array = [['a','b'], ['a', 'b','c'], ['a']]
result = set(x for l in array for x in l)
You can use itertools's chain to flatten your array and then call set on it:
from itertools import chain
array = [['a','b'], ['a', 'b','c'], ['a']]
print set(chain(*array))
If you are expecting a list object:
print list(set(chain(*array)))
The 2 top voted answers did not work for me, I'm not sure why (but I have integer lists). In the end I'm doing this:
unique_values = [list(x) for x in set(tuple(x) for x in aList)]
Try to this.
array = [['a','b'], ['a', 'b','c'], ['a']]
res=()
for item in array:
res = list(set(res) | set(item))
print res
Output:
['a', 'c', 'b']
array = [['a','b'], ['a', 'b','c'], ['a']]
unique_values = list(reduce(lambda i, j: set(i) | set(j), array))
You can use numpy.unique:
import numpy
import operator
print numpy.unique(reduce(operator.add, [['a','b'], ['a', 'b','c'], ['a']]))
# ['a' 'b' 'c']