Test MultipartFormData in Play 2.0 FakeRequest

Question

I\'m trying to create a function test for a Play 2 controller which takes multipart form data as input. There is no method currently in FakeRequest to support multipart form

Answer 1

You should use callAction to use withFormUrlEncodedBody

@Test
public void testMyAction() {
    running(fakeApplication(), new Runnable() {
        public void run() {                
            Map<String,String> data = new HashMap<String, Object>();
            data.put("param1", "test-1");
            data.put("param2", "test-2");
            data.put("file", file);

            Result result = callAction(
                controllers.whatever.action(),
                fakeRequest().withFormUrlEncodedBody(data)
            )
            ...
         }
     }
}

I use only Scala api for Play Framework 2 but I dont think you can test the multipart form using withFormUrlEncodedBody.

You can do in this way in Scala:

import play.api.libs.Files._
import play.api.mvc.MultipartFormData._

class MyTestSpec extends Specification {

    "mytest should bla bla bla" in {
        running(FakeApplication(aditionalConfiguration = inMemoryDatabase())) {
            val data = new MultipartFormData(Map(
                ("param1" -> Seq("test-1")),
                ("param2" -> Seq("test-2"))
            ), List(
                FilePart("payload", "message", Some("Content-Type: multipart/form-data"), play.api.libs.Files.TemporaryFile(new java.io.File("/tmp/pepe.txt")))
    ), List(), List())

            val Some(result) = routeAndCall(FakeRequest(POST, "/route/action", FakeHeaders(), data))
            ...
        }
    }
}

I guess you can translate it to Java, I don't know how to code it in Java sorry.

P.D: Sorry for my English I'm still learning

Answer 2

The easiest way to do this is to use Scala as follows:

val formData = Map(
  "param-1" -> Seq("value-1"),
  "param-2" -> Seq("value-2")
)
val result = routeAndCall(FakeRequest(POST, "/register").copy(body=formData))

This is assuming your controller method is of the form:

def register = Action(parse.tolerantFormUrlEncoded) { ... }

If you really must use Java, you don't have access to named parameters, so the 'copy' method above would have to be called in full. Also be careful to import the scala play.api.test.FakeRequest object, as the Java FakeRequest proxy doesn't have a copy method.

Answer 3

Here is a solution with callAction() in Java to create the multipart/form-data content for a request. It works at least in Play 2.2.3. My content-type was application/zip. You might want to change this.

@Test
public void callImport() throws Exception {
    File file = new File("test/yourfile.zip");
    FilePart<TemporaryFile> part = new MultipartFormData.FilePart<>(
            "file", "test/yourfile.zip",
            Scala.Option("application/zip"), new TemporaryFile(file));
    List<FilePart<TemporaryFile>> fileParts = new ArrayList<>();
    fileParts.add(part);
    scala.collection.immutable.List<FilePart<TemporaryFile>> files = scala.collection.JavaConversions
            .asScalaBuffer(fileParts).toList();
    MultipartFormData<TemporaryFile> formData = new MultipartFormData<TemporaryFile>(
            null, files, null, null);
    AnyContent anyContent = new AnyContentAsMultipartFormData(formData);

    Result result = callAction(
            controllers.routes.ref.ImportExport.import(),
            fakeRequest().withAnyContent(anyContent,
                    "multipart/form-data", "POST"));

    // Your Tests
    assertThat(status(result)).isEqualTo(OK);
}

Answer 4

Map<String, Object> data = new HashMap<String, Object>();
map.put("param1", "test-1");
map.put("param2", "test-2");

  final Http.RequestBuilder request = Helpers.fakeRequest()
                .method(POST)
                .bodyForm(formData)
                .uri("/register");

        final Result result = route(app, request);