How to remove time portion of date in C# in DateTime object only?

Question

I need to remove time portion of date time or probably have the date in following format in object form not in the form of string.

Answer 1

The Date property will return the date at midnight.

One option could be to get the individual values (day/month/year) separately and store it in the type you want.

var dateAndTime = DateTime.Now; 
int year = dateAndTime.Year;
int month = dateAndTime.Month;
int day = dateAndTime.Day;

string.Format("{0}/{1}/{2}", month, day, year);

Answer 2

You can't. A DateTime in .NET always have a time, defaulting to 00:00:00:000. The Date property of a DateTime is also a DateTime (!), thus having a time defaulting to 00:00:00:000 as well.

This is a shortage in the .NET Framework, and it could be argued that DateTime in .NET violates the Single Responsibility Principle.

Answer 3

This could be simply done this way:

var dateOnly = new DateTime(dateTime.Year, dateTime.Month, dateTime.Day)

Answer 4

To get only the date portion use the ToString() method,

example: DateTime.Now.Date.ToString("dd/MM/yyyy")

Note: The mm in the dd/MM/yyyy format must be capitalized

Answer 5

Use a bit of RegEx:

Regex.Match(Date.Now.ToString(), @"^.*?(?= )");

Produces a date in the format: dd/mm/yyyy

Answer 6

Use the method ToShortDateString. See the documentation http://msdn.microsoft.com/en-us/library/system.datetime.toshortdatestring.aspx

var dateTimeNow = DateTime.Now; // Return 00/00/0000 00:00:00
var dateOnlyString = dateTimeNow.ToShortDateString(); //Return 00/00/0000