Alternate table row color using CSS?

Answer 1

Most of the above codes won't work with IE version. The solution that works for IE+ other browsers is this.

   <style type="text/css">
      tr:nth-child(2n) {
             background-color: #FFEBCD;
        }
</style>

Answer 2

You can use nth-child(odd/even) selectors however not all browsers (ie 6-8, ff v3.0) support these rules hence why most solutions fall back to some form of javascript/jquery solution to add the classes to the rows for these non compliant browsers to get the tiger stripe effect.

Answer 3

We can use odd and even CSS rules and jQuery method for alternate row colors

Using CSS

table tr:nth-child(odd) td{
           background:#ccc;
}
table tr:nth-child(even) td{
            background:#fff;
}

Using jQuery

$(document).ready(function()
{
  $("table tr:odd").css("background", "#ccc");
  $("table tr:even").css("background", "#fff");
});

table tr:nth-child(odd) td{
           background:#ccc;
}
table tr:nth-child(even) td{
            background:#fff;
}

<table>
  <tr>
    <td>One</td>
    <td>one</td>
   </tr>
  <tr>
    <td>Two</td>
    <td>two</td>
  </tr>
</table>

Answer 4

can i write my html like this with use css ?

Yes you can but then you will have to use the :nth-child() pseudo selector (which has limited support though):

table.alternate_color tr:nth-child(odd) td{
   /* styles here */
}
table.alternate_color tr:nth-child(even) td{
   /* styles here */
}

Answer 5

There is a fairly easy way to do this in PHP, if I understand your query, I assume that you code in PHP and you are using CSS and javascript to enhance the output.

The dynamic output from the database will carry a for loop to iterate through results which are then loaded into the table. Just add a function call to the like this:

echo "<tr style=".getbgc($i).">";  //this calls the function based on the iteration of the for loop.

then add the function to the page or library file:

function getbgc($trcount)
{

$blue="\"background-color: #EEFAF6;\"";
$green="\"background-color: #D4F7EB;\"";
$odd=$trcount%2;
    if($odd==1){return $blue;}
    else{return $green;}    

}

Now this will alternate dynamically between colors at each newly generated table row.

It's a lot easier than messing about with CSS that doesn't work on all browsers.

Hope this helps.

Answer 6

$(document).ready(function()
{
  $("tr:odd").css({
    "background-color":"#000",
    "color":"#fff"});
});

tbody td{
  padding: 30px;
}

tbody tr:nth-child(odd){
  background-color: #4C8BF5;
  color: #fff;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table border="1">
<tbody>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>6</td>
<td>7</td>
<td>8</td>
</tr>
<tr>
<td>9</td>
<td>10</td>
<td>11</td>
<td>13</td>
</tr>
</tbody>
</table>

There is a CSS selector, really a pseudo-selector, called nth-child. In pure CSS you can do the following:

tr:nth-child(even) {
    background-color: #000000;
}

Note: No support in IE 8.

Or, if you have jQuery:

$(document).ready(function()
{
  $("tr:even").css("background-color", "#000000");
});