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XPath expression to select all XML child nodes except a specific list?

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挽巷
挽巷 2020-12-05 10:50

Here\'s the sample data:


    
        Empire Burlesque
        Bob Dylan
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  • 悲哀的现实
    2020-12-05 11:24

    I'd start experimenting with something like

    "//cd/*[(name() != 'price') and (name() != 'year')]"

    Or you just do normal recursive template matching with <xsl:apply-templates/>, and then have empty templates for <price/> and <year/> elements:

    <xsl:template match="price"/>
<xsl:template match="year"/>
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  • 南旧
    2020-12-05 11:41 
    <xsl:for-each select="//cd/*[not(self::price or self::year)]">

    But actually this is bad and unnecessarily complicated. Better:

    <xsl:template match="catalog">
  <html>
    <body>
      <xsl:apply-templates select="cd/*" />
    </body>
  </html>
</xsl:template>

<!-- this is an empty template to mute any unwanted elements -->
<xsl:template match="cd/price | cd/year" />

<!-- this is to output wanted elements -->
<xsl:template match="cd/*">
  <xsl:text>Current node: </xsl:text>
  <xsl:value-of select="."/>
  <br />
</xsl:template>

    Avoid <xsl:for-each>. Almost all of the time it is the wrong tool and should be substituted by <xsl:apply-templates> and <xsl:template>.

    The above works because of match expression specificity. match="cd/price | cd/year" is more specific than match="cd/*", so it is the preferred template for cd/price or cd/year elements. Don't try to exclude nodes, let them come and handle them by discarding them.

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