How do I convert a std::vector
to a double array[]
?
As to std::vector<int> vec
, vec to get int*
, you can use two method:
int* arr = &vec[0];
int* arr = vec.data();
If you want to convert any type T
vector to T* array
, just replace the above int
to T
.
I will show you why does the above two works, for good understanding?
std::vector
is a dynamic array essentially.
Main data member as below:
template <class T, class Alloc = allocator<T>>
class vector{
public:
typedef T value_type;
typedef T* iterator;
typedef T* pointer;
//.......
private:
pointer start_;
pointer finish_;
pointer end_of_storage_;
public:
vector():start_(0), finish_(0), end_of_storage_(0){}
//......
}
The range (start_, end_of_storage_)
is all the array memory the vector allocate;
The range(start_, finish_)
is all the array memory the vector used;
The range(finish_, end_of_storage_)
is the backup array memory.
For example, as to a vector vec. which has {9, 9, 1, 2, 3, 4} is pointer may like the below.
So &vec[0]
= start_ (address.) (start_ is equivalent to int* array head)
In c++11
the data()
member function just return start_
pointer data()
{
return start_; //(equivalent to `value_type*`, array head)
}
We can do this using data() method. C++11 provides this method.
#include<bits/stdc++.h>
using namespace std;
int main()
{
ios::sync_with_stdio(false);
vector<int>v = {7, 8, 9, 10, 11};
int *arr = v.data();
for(int i=0; i<v.size(); i++)
{
cout<<arr[i]<<" ";
}
return 0;
}
What for? You need to clarify: Do you need a pointer to the first element of an array, or an array?
If you're calling an API function that expects the former, you can do do_something(&v[0], v.size())
, where v
is a vector of double
s. The elements of a vector are contiguous.
Otherwise, you just have to copy each element:
double arr[100];
std::copy(v.begin(), v.end(), arr);
Ensure not only thar arr
is big enough, but that arr
gets filled up, or you have uninitialized values.
std::vector<double> vec;
double* arr = vec.data();