I know you can pass all a react components props to it\'s child component like this:
const ParentComponent = () => (
Parent
const ParentComponent = (props) => (
<div>
<h1>Parent Component</h1>
<ChildComponent {...props} />
</div>
);
const ChildComponent = ({prop1, ...rest}) =>{
<div>
<h1>Child Component with prop1={prop1}</h1>
<GrandChildComponent {...rest} />
</div>
}
const GrandChildComponent = ({prop2, prop3})=> {
<div>
<h1>Grand Child Component with prop2={prop1} and prop3={prop3}</h1>
</div>
}
But how do you then retrieve those props if the child component is stateless?
const ChildComponent = ({ *what goes here?* }) => (
<div>
<h1>Child Component</h1>
</div>
)
ChildComponent
holds the name and the props
will be the argument in the arrow function syntax just as you need:
const ChildComponent = props => (
<div>
<p>{props.value ? props.value : "No value."}</p>
</div>
);
If you Babel-it it will create something like this:
var ChildComponent = function ChildComponent(props) {
return React.createElement(
"div",
null,
React.createElement(
"p",
null,
props.value ? props.value : "No value."
)
);
};
You can use Spread Attributes reducing code bloat. This comes in the form of {'somearg':123, ...props}
or {...this.props}
, with the former allowing you to set some fields, while the latter is a complete copy. Here's an example with ParentClass.js
:
import React from 'react';
import SomeComponent from '../components/SomeComponent.js';
export default class ParentClass extends React.Component {
render() {
<SomeComponent
{...this.props}
/>
}
}
If I do, <ParentClass getCallBackFunc={() => this.getCallBackFunc()} />
, or if I do <ParentClass date={todaysdatevar} />
, the props getCallBackFunc
or date
will be available to the SomeComponent
class. This saves me an incredible amount of typing and/or copying/pasting.
Source: ReactJS.org: JSX In Depth, Specifying the React Element Type, Spread Attributes. Official POD:
If you already have props as an object, and you want to pass it in JSX, you can use ... as a “spread” operator to pass the whole props object. These two components are equivalent:
return <Greeting firstName="Ben" lastName="Hector" />; } function App2() { const props = {firstName: 'Ben', lastName: 'Hector'}; return <Greeting {...props} />; }```
Now, let's apply this to your code sample!
const ParentComponent = (props) => (
<div>
<h1>Parent Component</h1>
<ChildComponent {...props} />
</div>
);
When you write
const ChildComponent = ({ someProp }) => (
<div>
<h1>Child Component {someProp}</h1>
</div>
)
From all the props that you are passing to the childComponent
you are just destructuring to get only someProp
. If the number of props that you want to use in ChildComponents are countable(few) amongst the total number of props that are available, destructuring is a good option as it provides better readability.
Suppose you want to access all the props in the child component then you need not use {}
around the argument and then you can use it like props.someProp
const ChildComponent = (props) => (
<div>
<h1>Child Component {props.someProp}</h1>
</div>
)
For some reason, what seems to work for me is a variation on Shubham's answer above:
const ChildComponent = props => (
<div>
<h1>Child Component {props[0].someProp}</h1>
</div>
)
Using this
const ParentComponent = ({ prop1, prop2, prop3 }) => (
<div>
<h1>Parent Component</h1>
<ChildComponent {...{ prop1, prop2, prop3 }} />
</div>
);
const ChildComponent = ({ prop1, prop2, prop3 }) =>{
<div>
<h1>Child Component with prop1={prop1}</h1>
<h1>Child Component with prop2={prop2}</h1>
<h1>Child Component with prop2={prop3}</h1>
</div>
}