How do I sum the first value in each tuple in a list of tuples in Python?

Question

I have a list of tuples (always pairs) like this:

[(0, 1), (2, 3), (5, 7), (2, 1)]

I\'d like to find the sum of the first items in each pai

Answer 1

A version compatible with Python 2.3 is

sum([pair[0] for pair in list_of_pairs])

or in recent versions of Python, see this answer or this one.

Answer 2

If you have a very large list or a generator that produces a large number of pairs you might want to use a generator based approach. For fun I use itemgetter() and imap(), too. A simple generator based approach might be enough, though.

import operator
import itertools

idx0 = operator.itemgetter(0)
list_of_pairs = [(0, 1), (2, 3), (5, 7), (2, 1)]
sum(itertools.imap(idx0, list_of_pairs))

Note that itertools.imap() is available in Python >= 2.3. So you can use a generator based approach there, too.

Answer 3

Below is sample code, you can also specify the list range.

def test_lst_sum():
    lst = [1, 3, 5]
    print sum(lst)  # 9
    print sum(lst[1:])  # 8

    print sum(lst[5:])  # 0  out of range so return 0
    print sum(lst[5:-1])  # 0

    print sum(lst[1: -1])  # 3

    lst_tp = [('33', 1), ('88', 2), ('22', 3), ('44', 4)]
    print sum(x[1] for x in lst_tp[1:])  # 9

Answer 4

Obscure (but fun) answer:

>>> sum(zip(*list_of_pairs)[0])
9

Or when zip's are iterables only this should work:

>>> sum(zip(*list_of_pairs).__next__())
9

Answer 5

If you don't mind converting it to a numpy array, you can use np.sum over axis=0 as given here

Answer 6

                s,p=0,0
                for i in l:
                  s=s+i[0]
                  p=p+i[1]
               print(tuple(s,p))

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