Using variable in SQL LIKE statement

Question

I\'ve got a sproc (MSSQL 2k5) that will take a variable for a LIKE claus like so:

DECLARE @SearchLetter2 char(1)
SET @SearchLetter = \'t\'
SET @SearchLetter2         


        

Answer 1

As Andrew Brower says, but adding a trim

ALTER PROCEDURE <Name>
(
    @PartialName VARCHAR(50) = NULL
)

SELECT Name 
    FROM <table>
    WHERE Name LIKE '%' + LTRIM(RTRIM(@PartialName)) + '%'

Answer 2

DECLARE @SearchLetter2 char(1)

Set this to a longer char.

Answer 3

It may be as simple as LIKE '%%[%3]%%' being [%3] the input variable.

This works for me with SAP B1 9.1

Answer 4

We can write directly too...

DECLARE @SearchLetter CHAR(1) 

SET @SearchLetter = 'A' 

SELECT * 
FROM   CUSTOMERS 
WHERE  CONTACTNAME LIKE @SearchLetter + '%' 
       AND REGION = 'WY' 

or the following way as well if we have to append all the search characters then,

DECLARE @SearchLetter CHAR(1) 

SET @SearchLetter = 'A' + '%' 

SELECT * 
FROM   CUSTOMERS 
WHERE  CONTACTNAME LIKE @SearchLetter 
       AND REGION = 'WY' 

Both these will work

Answer 5

I had also problem using local variables in LIKE.
Important is to know: how long is variable.
Below, ORDER_NO is 50 characters long, so You can not use: LIKE @ORDER_NO, because in the end will be spaces.
You need to trim right side of the variable first.
Like this:

DECLARE @ORDER_NO char(50)
SELECT @ORDER_NO = 'OR/201910/0012%'

SELECT * FROM orders WHERE ord_no LIKE RTRIM(@ORDER_NO)

Answer 6

This works for me on the Northwind sample DB, note that SearchLetter has 2 characters to it and SearchLetter also has to be declared for this to run:

declare @SearchLetter2 char(2)
declare @SearchLetter char(1)
Set @SearchLetter = 'A'
Set @SearchLetter2 = @SearchLetter+'%'
select * from Customers where ContactName like @SearchLetter2 and Region='WY'