downloading an excel file from the web in python

Question

I have the following web address:

dls = \"http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls\"

I tried to download the file:

Answer 1

To add on to Fedalto's requests suggestion (+1), but make it more Pythonic with a context manager:

import requests
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
resp = requests.get(dls)
with open('test.xls', 'wb') as output:
    output.write(resp.content)

Answer 2

I suggest using requests:

import requests
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
resp = requests.get(dls)

output = open('test.xls', 'wb')
output.write(resp.content)
output.close()

To get requests installed:

pip install requests

Answer 3

This would save the excel file in the same folder that the script was ran from.

import urllib
dls = "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls"
urllib.request.urlretrieve(dls, "test.xls")  # For Python 3
# urllib.urlretrieve(dls, "test.xls")  # For Python 2

Answer 4

Two issues, one with the code (below), the other that the URL is bad. A (modern) web browser will automatically correct "http://www.muellerindustries.com/uploads/pdf/UW SPD0114.xls" to "http://www.muellerindustries.com/uploads/pdf/UW%20SPD0114.xls" but Python doesn't.

This code works for me on python 3.x

import urllib
outfilename = "test.xls"
url_of_file = "http://www.muellerindustries.com/uploads/pdf/UW%20SPD0114.xls"
urllib.request.urlretrieve(url_of_file, outfilename) 

Which gets me the file.