jQuery AJAX form data serialize using PHP

Question

I am stuck in my code, I need to send data from the form to the check.php page and then process it.

This is my code:

The AJAX part:

Answer 1

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
    var form=$("#myForm");
    $("#smt").click(function(){
        $.ajax({
            type:"POST",
            url:form.attr("action"),
            data:form.serialize(),
            success: function(response){
                console.log(response);  
            }
        });
    });
});
</script>

This is perfect code , there is no problem.. You have to check that in php script.

Answer 2

Change your code as follows -

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
        type:"POST",
        url:form.attr("action"),
        data:form.serialize(),

        success: function(response){
        if(response == 1){
              $("#err").html("Hi Tony");//updated
        }  else {
            $("#err").html("I dont know you.");//updated
        }
        }
    });
});
});
</script>

PHP -

<?php
$user=$_POST['user'];
$pass=$_POST['pass'];

if($user=="tony")
{
    echo 1;   
}
else
{
    echo 0;    
}
?>

Answer 3

I just had the same problem: You have to unserialize the data on the php side.

Add to the beginning of your php file (Attention this short version would replace all other post variables):

parse_str($_POST["data"], $_POST);

Answer 4

Your problem is in your php file. When you use jquery serialize() method you are sending a string, so you can not treat it like an array. Make a var_dump($_post) and you will see what I am talking about.

Answer 5

Try this its working..

    <script>
      $(function () {
          $('form').on('submit', function (e) {
              e.preventDefault();
              $.ajax({
                  type: 'post',
                  url: '<?php echo base_url();?>student_ajax/insert',
                  data: $('form').serialize(),
                  success: function (response) {
                      alert('form was submitted');
                  }
                  error:function() {
                      alert('fail');
                  }
              });
          });
      });
    </script>

Answer 6

Try this

 $(document).ready(function(){
    var form=$("#myForm");
    $("#smt").click(function(){
    $.ajax({
            type:"POST",
            url:form.attr("action"),
            data:$("#myForm input").serialize(),//only input
            success: function(response){
                console.log(response);  
            }
        });
    });
    });