Detect if a user has typed an emoji character in UITextView

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醉话见心 2020-12-05 08:13

I have a UITextView and I need to detect if a user enters an emoji character.

I would think that just checking the unicode value of the newest character would suffic

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  • 2020-12-05 09:09

    Swift's String type has a property .isEmoji

    Best to check the documentation for the isEmojiPresentation caveat

    https://developer.apple.com/documentation/swift/unicode/scalar/properties/3081577-isemoji

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  • 2020-12-05 09:11

    Over the years these emoji-detecting solutions keep breaking as Apple adds new emojis w/ new methods (like skin-toned emojis built by pre-cursing a character with an additional character), etc.

    I finally broke down and just wrote the following method which works for all current emojis and should work for all future emojis.

    The solution creates a UILabel with the character and a black background. CG then takes a snapshot of the label and I scan all pixels in the snapshot for any non solid-black pixels. The reason I add the black background is to avoid issues of false-coloring due to Subpixel Rendering

    The solution runs VERY fast on my device, I can check hundreds of characters a second, but it should be noted that this is a CoreGraphics solution and should not be used heavily like you could with a regular text method. Graphics processing is data heavy so checking thousands of characters at once could result in noticeable lag.

    -(BOOL)isEmoji:(NSString *)character {
    
        UILabel *characterRender = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 1, 1)];
        characterRender.text = character;
        characterRender.backgroundColor = [UIColor blackColor];//needed to remove subpixel rendering colors
        [characterRender sizeToFit];
    
        CGRect rect = [characterRender bounds];
        UIGraphicsBeginImageContextWithOptions(rect.size,YES,0.0f);
        CGContextRef contextSnap = UIGraphicsGetCurrentContext();
        [characterRender.layer renderInContext:contextSnap];
        UIImage *capturedImage = UIGraphicsGetImageFromCurrentImageContext();
        UIGraphicsEndImageContext();
    
        CGImageRef imageRef = [capturedImage CGImage];
        NSUInteger width = CGImageGetWidth(imageRef);
        NSUInteger height = CGImageGetHeight(imageRef);
        CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
        unsigned char *rawData = (unsigned char*) calloc(height * width * 4, sizeof(unsigned char));
        NSUInteger bytesPerPixel = 4;
        NSUInteger bytesPerRow = bytesPerPixel * width;
        NSUInteger bitsPerComponent = 8;
        CGContextRef context = CGBitmapContextCreate(rawData, width, height,
                                                     bitsPerComponent, bytesPerRow, colorSpace,
                                                     kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big);
        CGColorSpaceRelease(colorSpace);
    
        CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef);
        CGContextRelease(context);
    
        BOOL colorPixelFound = NO;
    
        int x = 0;
        int y = 0;
        while (y < height && !colorPixelFound) {
            while (x < width && !colorPixelFound) {
    
                NSUInteger byteIndex = (bytesPerRow * y) + x * bytesPerPixel;
    
                CGFloat red = (CGFloat)rawData[byteIndex];
                CGFloat green = (CGFloat)rawData[byteIndex+1];
                CGFloat blue = (CGFloat)rawData[byteIndex+2];
    
                CGFloat h, s, b, a;
                UIColor *c = [UIColor colorWithRed:red green:green blue:blue alpha:1.0f];
                [c getHue:&h saturation:&s brightness:&b alpha:&a];
    
                b /= 255.0f;
    
                if (b > 0) {
                    colorPixelFound = YES;
                }
    
                x++;
            }
            x=0;
            y++;
        }
    
        return colorPixelFound;
    
    }
    
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  • 2020-12-05 09:11

    First let's address your "55357 method" – and why it works for many emoji characters.

    In Cocoa, an NSString is a collection of unichars, and unichar is just a typealias for unsigned short which is the same as UInt16. Since the maximum value of UInt16 is 0xffff, this rules out quite a few emoji from being able to fit into one unichar, as only two out of the six main Unicode blocks used for emoji fall under this range:

    • Miscellaneous Symbols (U+2600–U+26FF)
    • Dingbats (U+2700–U+27BF)

    These blocks contain 113 emoji, and an additional 66 emoji that can be represented as a single unichar can be found spread around various other blocks. However, these 179 characters only represent a fraction of the 1126 emoji base characters, the rest of which must be represented by more than one unichar.

    Let's analyse your code:

    unichar unicodevalue = [text characterAtIndex:0];
    

    What's happening is that you're simply taking the first unichar of the string, and while this works for the previously mentioned 179 characters, it breaks apart when you encounter a UTF-32 character, since NSString converts everything into UTF-16 encoding. The conversion works by substituting the UTF-32 value with surrogate pairs, which means that the NSString now contains two unichars.

    And now we're getting to why the number 55357, or 0xd83d, appears for many emoji: when you only look at the first UTF-16 value of a UTF-32 character you get the high surrogate, each of which have a span of 1024 low surrogates. The range for the high surrogate 0xd83d is U+1F400–U+1F7FF, which starts in the middle of the largest emoji block, Miscellaneous Symbols and Pictographs (U+1F300–U+1F5FF), and continues all the way up to Geometric Shapes Extended (U+1F780–U+1F7FF) – containing a total of 563 emoji, and 333 non-emoji characters within this range.

    So, an impressive 50% of emoji base characters have the the high surrogate 0xd83d, but these deduction methods still leave 384 emoji characters unhandled, along with giving false positives for at least as many.


    So, how can you detect whether a character is an emoji or not?

    I recently answered a somewhat related question with a Swift implementation, and if you want to, you can look at how emoji are detected in this framework, which I created for the purpose of replacing standard emoji with custom images.

    Anyhow, what you can do is extract the UTF-32 code point from the characters, which we'll do according to the specification:

    - (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
    
        // Get the UTF-16 representation of the text.
        unsigned long length = text.length;
        unichar buffer[length];
        [text getCharacters:buffer];
    
        // Initialize array to hold our UTF-32 values.
        NSMutableArray *array = [[NSMutableArray alloc] init];
    
        // Temporary stores for the UTF-32 and UTF-16 values.
        UTF32Char utf32 = 0;
        UTF16Char h16 = 0, l16 = 0;
    
        for (int i = 0; i < length; i++) {
            unichar surrogate = buffer[i];
    
            // High surrogate.
            if (0xd800 <= surrogate && surrogate <= 0xd83f) {
                h16 = surrogate;
                continue;
            }
            // Low surrogate.
            else if (0xdc00 <= surrogate && surrogate <= 0xdfff) {
                l16 = surrogate;
    
                // Convert surrogate pair to UTF-32 encoding.
                utf32 = ((h16 - 0xd800) << 10) + (l16 - 0xdc00) + 0x10000;
            }
            // Normal UTF-16.
            else {
                utf32 = surrogate;
            }
    
            // Add UTF-32 value to array.
            [array addObject:[NSNumber numberWithUnsignedInteger:utf32]];
        }
    
        NSLog(@"%@ contains values:", text);
    
        for (int i = 0; i < array.count; i++) {
            UTF32Char character = (UTF32Char)[[array objectAtIndex:i] unsignedIntegerValue];
            NSLog(@"\t- U+%x", character);
        }
    
        return YES;
    }
    

    Typing "

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