Converting a string to a formatted date-time string using Python

Question

I\'m trying to convert a string \"20091229050936\" into \"05:09 29 December 2009 (UTC)\"

>>>import time
>>>s = time.strptime(\"200912290509         


        

Answer 1

You can use easy_date to make it easy:

import date_converter
my_datetime = date_converter.string_to_string("20091229050936", "%Y%m%d%H%M%S", "%H:%M %d %B %Y (UTC)")

Answer 2

For me this is the best and it works on Google App Engine as well

Example showing UTC-4

import datetime   
UTC_OFFSET = 4
local_datetime = datetime.datetime.now()
print (local_datetime - datetime.timedelta(hours=UTC_OFFSET)).strftime("%Y-%m-%d %H:%M:%S")

Answer 3

time.strptime returns a time_struct; time.strftime accepts a time_struct as an optional parameter:

>>>s = time.strptime(page.editTime(), "%Y%m%d%H%M%S")
>>>print time.strftime('%H:%M %d %B %Y (UTC)', s)

gives 05:09 29 December 2009 (UTC)

Answer 4

For datetime objects, strptime is a static method of the datetime class, not a free function in the datetime module:

>>> import datetime
>>> s = datetime.datetime.strptime("20091229050936", "%Y%m%d%H%M%S")
>>> print s.strftime('%H:%M %d %B %Y (UTC)')
05:09 29 December 2009 (UTC)

Answer 5

from datetime import datetime
s = datetime.strptime("20091229050936", "%Y%m%d%H%M%S")
print("{:%H:%M %d %B %Y (UTC)}".format(s))