Turn a single number into single digits Python [duplicate]

Answer 1

If you want to change your number into a list of those numbers, I would first cast it to a string, then casting it to a list will naturally break on each character:

[int(x) for x in str(n)]

Answer 2

This can be done quite easily if you:

1. Use str to convert the number into a string so that you can iterate over it.

2. Use a list comprehension to split the string into individual digits.

3. Use int to convert the digits back into integers.

Below is a demonstration:

>>> n = 43365644
>>> [int(d) for d in str(n)]
[4, 3, 3, 6, 5, 6, 4, 4]
>>>

Answer 3

The easiest way is to turn the int into a string and take each character of the string as an element of your list:

>>> n = 43365644 
>>> digits = [int(x) for x in str(n)]
>>> digits
[4, 3, 3, 6, 5, 6, 4, 4]
>>> lst.extend(digits)  # use the extends method if you want to add the list to another

It involves a casting operation, but it's readable and acceptable if you don't need extreme performance.

Answer 4

Here's a way to do it without turning it into a string first (based on some rudimentary benchmarking, this is about twice as fast as stringifying n first):

>>> n = 43365644
>>> [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10))-1, -1, -1)]
[4, 3, 3, 6, 5, 6, 4, 4]