Ignore case in glob() on Linux

Question

I\'m writing a script which will have to work on directories which are modified by hand by Windows and Linux users alike. The Windows users tend to not care at all about cas

Answer 1

Here is my non-recursive file search for Python with glob like behavior for Python 3.5+

# Eg: find_files('~/Downloads', '*.Xls', ignore_case=True)
def find_files(path: str, glob_pat: str, ignore_case: bool = False):
    rule = re.compile(fnmatch.translate(glob_pat), re.IGNORECASE) if ignore_case \
            else re.compile(fnmatch.translate(glob_pat))
    return [n for n in os.listdir(os.path.expanduser(path)) if rule.match(n)]

Note: This version handles home directory expansion

Answer 2

Use case-insensitive regexes instead of glob patterns. fnmatch.translate generates a regex from a glob pattern, so

re.compile(fnmatch.translate(pattern), re.IGNORECASE)

gives you a case-insensitive version of a glob pattern as a compiled RE.

Keep in mind that, if the filesystem is hosted by a Linux box on a Unix-like filesystem, users will be able to create files foo, Foo and FOO in the same directory.

Answer 3

Riffing off of @Timothy C. Quinn's answer, this modification allows the use of wildcards anywhere in the path. This is admittedly only case insensitive for the glob_pat argument.

import re
import os
import fnmatch
import glob

def find_files(path: str, glob_pat: str, ignore_case: bool = False):
    rule = re.compile(fnmatch.translate(glob_pat), re.IGNORECASE) if ignore_case \
            else re.compile(fnmatch.translate(glob_pat))
    return [n for n in glob.glob(os.path.join(path, '*')) if rule.match(n)]

Answer 4

You can replace each alphabetic character c with [cC], via

import glob
def insensitive_glob(pattern):
    def either(c):
        return '[%s%s]' % (c.lower(), c.upper()) if c.isalpha() else c
    return glob.glob(''.join(map(either, pattern)))

Answer 5

Non recursively

In order to retrieve the files (and files only) of a directory "path", with "globexpression":

list_path = [i for i in os.listdir(path) if os.path.isfile(os.path.join(path, i))]
result = [os.path.join(path, j) for j in list_path if re.match(fnmatch.translate(globexpression), j, re.IGNORECASE)]

Recursively

with walk:

result = []
for root, dirs, files in os.walk(path, topdown=True):
  result += [os.path.join(root, j) for j in files \
             if re.match(fnmatch.translate(globexpression), j, re.IGNORECASE)]

Better also compile the regular expression, so instead of

re.match(fnmatch.translate(globexpression)

do (before the loop):

reg_expr = re.compile(fnmatch.translate(globexpression), re.IGNORECASE)

and then replace in the loop:

  result += [os.path.join(root, j) for j in files if re.match(reg_expr, j)]

Answer 6

Depending on your case, you might use .lower() on both file pattern and results from folder listing and only then compare the pattern with the filename