I have the following:
let mut my_number = 32.90;
How do I print the type of my_number
?
Using type
and
You can also use the simple approach of using the variable in println!("{:?}", var)
. If Debug
is not implemented for the type, you can see the type in the compiler's error message:
mod some {
pub struct SomeType;
}
fn main() {
let unknown_var = some::SomeType;
println!("{:?}", unknown_var);
}
(playpen)
It's dirty but it works.
If you merely wish to find out the type of a variable and are willing to do it at compile time, you can cause an error and get the compiler to pick it up.
For example, set the variable to a type which doesn't work:
let mut my_number: () = 32.90;
// let () = x; would work too
error[E0308]: mismatched types
--> src/main.rs:2:29
|
2 | let mut my_number: () = 32.90;
| ^^^^^ expected (), found floating-point number
|
= note: expected type `()`
found type `{float}`
Or call an invalid method:
let mut my_number = 32.90;
my_number.what_is_this();
error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
--> src/main.rs:3:15
|
3 | my_number.what_is_this();
| ^^^^^^^^^^^^
Or access an invalid field:
let mut my_number = 32.90;
my_number.what_is_this
error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
--> src/main.rs:3:15
|
3 | my_number.what_is_this
| ^^^^^^^^^^^^
These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}
” in all three examples; this is a partially resolved type which could end up f32
or f64
, depending on how you use it. “{float}
” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64
¹. (An unqualified integer literal will default to i32
.)
See also:
¹ There may still be ways of baffling the compiler so that it can’t decide between f32
and f64
; I’m not sure. It used to be as simple as 32.90.eq(&32.90)
, but that treats both as f64
now and chugs along happily, so I don’t know.
You can use the std::any::type_name function. This doesn't need a nightly compiler or an external crate, and the results are quite correct:
fn print_type_of<T>(_: &T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(&s); // &str
print_type_of(&i); // i32
print_type_of(&main); // playground::main
print_type_of(&print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(&{ || "Hi!" }); // playground::main::{{closure}}
}
Be warned: as said in the documentation, this information must be used for a debug purpose only:
This is intended for diagnostic use. The exact contents and format of the string are not specified, other than being a best-effort description of the type.
If you want your type representation to stay the same between compiler versions, you should use a trait, like in the phicr's answer.
There is an unstable function std::intrinsics::type_name that can get you the name of a type, though you have to use a nightly build of Rust (this is unlikely to ever work in stable Rust). Here’s an example:
#![feature(core_intrinsics)]
fn print_type_of<T>(_: &T) {
println!("{}", unsafe { std::intrinsics::type_name::<T>() });
}
fn main() {
print_type_of(&32.90); // prints "f64"
print_type_of(&vec![1, 2, 4]); // prints "std::vec::Vec<i32>"
print_type_of(&"foo"); // prints "&str"
}
** UPDATE ** This has not been verified to work any time recently.
I put together a little crate to do this based off vbo's answer. It gives you a macro to return or print out the type.
Put this in your Cargo.toml file:
[dependencies]
t_bang = "0.1.2"
Then you can use it like so:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}