Getting the current Fragment instance in the viewpager

Question

Below is my code which has 3 Fragment classes each embedded with each of the 3 tabs on ViewPager. I have a menu option. As shown in the onOpt

Answer 1

by selecting an option, I need to update the fragment that is currently visible.

To get a reference to currently visible fragment, assume you have a reference to ViewPager as mPager. Then following steps will get a reference to currentFragment:

1. PageAdapter adapter = mPager.getAdapter();
2. int fragmentIndex = mPager.getCurrentItem();
3. FragmentStatePagerAdapter fspa = (FragmentStatePagerAdapter)adapter;
4. Fragment currentFragment = fspa.getItem(fragmentIndex);

The only cast used line 3 is valid usually. FragmentStatePagerAdapter is an useful adapter for a ViewPager.

Answer 2

When we use the viewPager, a good way to access the fragment instance in activity is instantiateItem(viewpager,index). //index- index of fragment of which you want instance.

for example I am accessing the fragment instance of 1 index-

Fragment fragment = (Fragment) viewPageradapter.instantiateItem(viewPager, 1);

if (fragment != null && fragment instanceof MyFragment) {      
 ((MyFragment) fragment).callYourFunction();

}

Answer 3

This is more future-proof than the accepted answer:

public class MyFragmentPagerAdapter extends FragmentPagerAdapter {

    /* ------------------------------------------------------------------------------------------ */
    // region Private attributes :

    private Context _context;
    private FragmentManager _fragmentManager;
    private Map<Integer, String> _fragmentsTags = new HashMap<>();

    // endregion
    /* ------------------------------------------------------------------------------------------ */



    /* ------------------------------------------------------------------------------------------ */
    // region Constructor :

    public MyFragmentPagerAdapter(Context context, FragmentManager fragmentManager) {

        super(fragmentManager);

        _context = context;
        _fragmentManager = fragmentManager;
    }

    // endregion
    /* ------------------------------------------------------------------------------------------ */



    /* ------------------------------------------------------------------------------------------ */
    // region FragmentPagerAdapter methods :

    @Override
    public int getCount() { return 2; }

    @Override
    public Fragment getItem(int position) {

        if(_fragmentsTags.containsKey(position)) {

            return _fragmentManager.findFragmentByTag(_fragmentsTags.get(position));
        }
        else {

            switch (position) {

                case 0 : { return Fragment.instantiate(_context, Tab1Fragment.class.getName()); }
                case 1 : { return Fragment.instantiate(_context, Tab2Fragment.class.getName()); }
            }
        }

        return null;
    }

    @Override
    public Object instantiateItem(ViewGroup container, int position) {

        // Instantiate the fragment and get its tag :
        Fragment result = (Fragment) super.instantiateItem(container, position);
        _fragmentsTags.put(position, result.getTag());

        return result;
    }

    // endregion
    /* ------------------------------------------------------------------------------------------ */
}

Answer 4

FragmentStatePagerAdapter has a private instance variable called mCurrentPrimaryItem of type Fragment. One can only wonder why Android devs did not supplied it with a getter. This variable is instantiated in setPrimaryItem() method. So, override this method in such a way for you to get the reference to this variable. I simply ended up with declaring my own mCurrentPrimaryItem and copying the contents of setPrimaryItem() to my override.

In your implementation of FragmentStatePagerAdapter:

private Fragment mCurrentPrimaryItem = null;

@Override
public void setPrimaryItem(ViewGroup container, int position, Object object) {
    Fragment fragment = (Fragment)object;
    if (fragment != mCurrentPrimaryItem) {
        if (mCurrentPrimaryItem != null) {
            mCurrentPrimaryItem.setMenuVisibility(false);
            mCurrentPrimaryItem.setUserVisibleHint(false);
        }
        if (fragment != null) {
            fragment.setMenuVisibility(true);
            fragment.setUserVisibleHint(true);
        }
        mCurrentPrimaryItem = fragment;
    }
}

public TasksListFragment getCurrentFragment() {
    return (YourFragment) mCurrentPrimaryItem;
}

Answer 5

You can define the PagerAdapter like this then you will able to get any Fragment in ViewPager.

private class PagerAdapter extends FragmentPagerAdapter {
    private final List<Fragment> mFragmentList = new ArrayList<>();

    public PagerAdapter(FragmentManager fm) {
        super(fm);
    }

    @Override
    public Fragment getItem(int position) {
        return mFragmentList.get(position);
    }

    @Override
    public int getCount() {
        return mFragmentList.size();
    }

    public void addFragment(Fragment fragment) {
        mFragmentList.add(fragment);
    }
}

To get the current Fragment

Fragment currentFragment = mPagerAdapter.getItem(mViewPager.getCurrentItem());

Answer 6

This is the simplest hack:

fun getCurrentFragment(): Fragment? {
    return if (count == 0) null
    else instantiateItem(view_pager, view_pager.currentItem) as? Fragment
}

(kotlin code)

Just call instantiateItem(viewPager, viewPager.getCurrentItem() and cast it to Fragment. Your item would already be instantiated. To be sure you can add a check for getCount.

Works with both FragmentPagerAdapter and FragmentStatePagerAdapter!