How to find the last day of the month from date?

Question

How can I get the last day of the month in PHP?

Given:

$a_date = \"2009-11-23\"

I want 2009-11-30; and given

$a_dat         


        

Answer 1

Nowadays DateTime does this quite conveniently if you have month and year you can

$date = new DateTime('last day of '.$year.'-'.$month);

From another DateTime object that would be

$date = new DateTime('last day of '.$otherdate->format('Y-m'));

Answer 2

You can use "t" in date function to get the number of day in a particular month.

The code will be something like this:

function lastDateOfMonth($Month, $Year=-1) {
    if ($Year < 0) $Year = 0+date("Y");
    $aMonth         = mktime(0, 0, 0, $Month, 1, $Year);
    $NumOfDay       = 0+date("t", $aMonth);
    $LastDayOfMonth = mktime(0, 0, 0, $Month, $NumOfDay, $Year);
    return $LastDayOfMonth;
}

for($Month = 1; $Month <= 12; $Month++)
    echo date("Y-n-j", lastDateOfMonth($Month))."\n";

The code is self-explained. So hope it helps.

Answer 3

What is wrong - The most elegant for me is using DateTime

I wonder I do not see DateTime::createFromFormat, one-liner

$lastDay = \DateTime::createFromFormat("Y-m-d", "2009-11-23")->format("Y-m-t");

Answer 4

There are ways to get last day of month.

//to get last day of current month
echo date("t", strtotime('now'));

//to get last day from specific date
$date = "2014-07-24";
echo date("t", strtotime($date));

//to get last day from specific date by calendar
$date = "2014-07-24";
$dateArr=explode('-',$date);
echo cal_days_in_month(CAL_GREGORIAN, $dateArr[1], $dateArr[0]);