How to find the last day of the month from date?

Question

How can I get the last day of the month in PHP?

Given:

$a_date = \"2009-11-23\"

I want 2009-11-30; and given

$a_dat         


        

Answer 1

I know this is a little bit late but i think there is a more elegant way of doing this with PHP 5.3+ by using the DateTime class :

$date = new DateTime('now');
$date->modify('last day of this month');
echo $date->format('Y-m-d');

Answer 2

t returns the number of days in the month of a given date (see the docs for date):

$a_date = "2009-11-23";
echo date("Y-m-t", strtotime($a_date));

Answer 3

Your solution is here..

$lastday = date('t',strtotime('today'));

Answer 4

function first_last_day($string, $first_last, $format) {
    $result = strtotime($string);
    $year = date('Y',$result);
    $month = date('m',$result);
    $result = strtotime("{$year}-{$month}-01");
    if ($first_last == 'last'){$result = strtotime('-1 second', strtotime('+1 month', $result)); }
    if ($format == 'unix'){return $result; }
    if ($format == 'standard'){return date('Y-m-d', $result); }
}

http://zkinformer.com/?p=134

Answer 5

An other way using mktime and not date('t') :

$dateStart= date("Y-m-d", mktime(0, 0, 0, 10, 1, 2016)); //2016-10-01
$dateEnd = date("Y-m-d", mktime(0, 0, 0, 11, 0, 2016)); //This will return the last day of october, 2016-10-31 :)

So this way it calculates either if it is 31,30 or 29

Answer 6

The code using strtotime() will fail after year 2038. (as given in the first answer in this thread) For example try using the following:

$a_date = "2040-11-23";
echo date("Y-m-t", strtotime($a_date));

It will give answer as: 1970-01-31

So instead of strtotime, DateTime function should be used. Following code will work without Year 2038 problem:

$d = new DateTime( '2040-11-23' ); 
echo $d->format( 'Y-m-t' );