Difference between using StringTokenizer and String.split( )? [duplicate]

Answer 1

Read this

StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

Answer 2

I have the following program,

The string "x" is a tab separated 12s34;

    public class Testoken {
        public static void main(String[] args) {
            String x = "1   2   s       3           4   ";
            StringTokenizer st = new StringTokenizer(x,"\t");
            int i = 0;
            while(st.hasMoreTokens()){
                System.out.println("token-->"+st.nextToken());            
                i++;
            }
            System.out.println("i-->"+i);//elements from tokenizer
            String [] a = x.split("\t");
            System.out.println("length--->"+a.length);
            for(int y = 0;y<a.length;y++){
            System.out.println("value-->"+a[y]);//elements from split
            }
        }
    }   





Output: 

token-->1 
token-->2 
token-->s 
token-->3 
token-->4 
i-->5 
length--->8 
value-->1 
value-->2 
value-->s 
value--> 
value-->3 
value--> 
value--> 
value-->4

Answer 3

http://docs.oracle.com/javase/6/docs/api/java/util/StringTokenizer.html say:

StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

So I would say, don't change it and show that line to the person who recommended refactoring it. Maybe they have old information or another good reason to tell you.

Answer 4

Take a look at the JavaDocs

StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

The following example illustrates how the String.split method can be used to break up a string into its basic tokens:

 String[] result = "this is a test".split("\\s");
 for (int x=0; x<result.length; x++)
     System.out.println(result[x]);

Answer 5

String#split accepts a regular expression whether StringTokenizer just accepts a String by which will split the string. You should always stick to the String#split, it's more robust then StringTokenizer.