Java Generics Wildcarding With Multiple Classes

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名媛妹妹
名媛妹妹 2020-11-22 08:37

I want to have a Class object, but I want to force whatever class it represents to extend class A and implement interface B.

I can do:

Class

        
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  • 2020-11-22 09:08

    Here's how you would do it in Kotlin

    fun <T> myMethod(item: T) where T : ClassA, T : InterfaceB {
        //your code here
    }
    
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  • 2020-11-22 09:16

    Actually, you can do what you want. If you want to provide multiple interfaces or a class plus interfaces, you have to have your wildcard look something like this:

    <T extends ClassA & InterfaceB>
    

    See the Generics Tutorial at sun.com, specifically the Bounded Type Parameters section, at the bottom of the page. You can actually list more than one interface if you wish, using & InterfaceName for each one that you need.

    This can get arbitrarily complicated. To demonstrate, see the JavaDoc declaration of Collections#max, which (wrapped onto two lines) is:

    public static <T extends Object & Comparable<? super T>> T
                                               max(Collection<? extends T> coll)
    

    why so complicated? As said in the Java Generics FAQ: To preserve binary compatibility.

    It looks like this doesn't work for variable declaration, but it does work when putting a generic boundary on a class. Thus, to do what you want, you may have to jump through a few hoops. But you can do it. You can do something like this, putting a generic boundary on your class and then:

    class classB { }
    interface interfaceC { }
    
    public class MyClass<T extends classB & interfaceC> {
        Class<T> variable;
    }
    

    to get variable that has the restriction that you want. For more information and examples, check out page 3 of Generics in Java 5.0. Note, in <T extends B & C>, the class name must come first, and interfaces follow. And of course you can only list a single class.

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  • 2020-11-22 09:17

    You can't do it with "anonymous" type parameters (ie, wildcards that use ?), but you can do it with "named" type parameters. Simply declare the type parameter at method or class level.

    import java.util.List;
    interface A{}
    interface B{}
    public class Test<E extends B & A, T extends List<E>> {
        T t;
    }
    
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