SQL LIKE % inside array

Question

I know how to perform an SQL LIKE % query for a single value like so:

SELECT * FROM users WHERE name LIKE %tom%;

but how do I do this if th

Answer 1

Many SQL systems let you push it as a character value. CHAR(10) = Linefeed. So, occasionally, instead of working out all the escape coding, you can push single quotes, double quotes and other things into a sql string this way, without too many other coding issues.

-Just a hint.

Answer 2

i just took the code of 472084.

$sql = array('0'); // Stop errors when $words is empty

foreach($words as $word){
    $sql[] = 'name LIKE %'.$word.'%'
}

$sql = 'SELECT * FROM users WHERE '.implode(" OR ", $sql);

For my self, i had to modify it because it's returned me an error SQL. I Post it for people who gonna read the thread.

foreach($words as $word){
    $sql[] = 'name LIKE \'%'.$word.'%\'';
}

$sql = 'SELECT * FROM users WHERE '.implode(" OR ", $sql);

The difference between them is about quote, my mysql DB said there is a problem ! so i had to escape quote from $sql[] = 'name LIKE %'.$word.'%' and now it's work perfectly.