Best way to flatten JS object (keys and values) to a single depth array

Question

I have written this small function to get all keys and values of an object and store them into an array. The object might contain arrays as values...

Object {

Answer 1

This solution can handle deeply nested objects

const isObject = o => o && typeof o === 'object' && !(o instanceof Date);

const flattenObject = obj => Object.entries(obj).reduce((acc, [key, val]) => ({
  ...acc, ...(isObject(val) ? flattenObject(val) : { [key]: val })
}), {});

Remember that this function returns an empty object for strings, dates, numbers, etc.

Answer 2

Generate an array of tuples (two-element arrays) of keys and values (which might themselves be arrays), then deep-flatten it.

function flattenObject(obj) { 
      return flatten(Object.keys(obj).map(k => [toNumber(k), obj[k]]));
}

// Substitute your own favorite flattening algorithm.
const flatten = a => Array.isArray(a) ? [].concat(...a.map(flatten)) : a;

// Convert to number, if you can.
const toNumber = n => isNaN(+n) ? n : +n;

console.log(flattenObject({a: [1, 2], b: 3, 0: [1, 2, 3, 4, 5]}));

Answer 3

Flattening Object can be done using recursion as below :

Sample Input

  let obj = {
    name: "test",
    address: {
    personal: "abc", 
    office: {
       building : 'random'
       street : 'some street',
    }
    }
}

Expected Output

{
    name : "test",
    address_personal: "abc"
    address_office_building: "random"
    address_office_street: "some street"
}

My Solution

  function flattenObj(obj, parent, res = {}){
    for(let key in obj){
        let propName = parent ? parent + '_' + key : key;
        if(typeof obj[key] == 'object'){
            flattenObj(obj[key], propName, res);
        } else {
            res[propName] = obj[key];
        }
    }
    return res;
}

Hope it helps

Answer 4

I wanted to flatten my deep object to one level depth. None of the above solutions worked for me.

My input:

{
    "user": {
        "key_value_map": {
            "CreatedDate": "123424",
            "Department": {
                "Name": "XYZ"
            }
        }
    }
}

Expected output:

{
    "user.key_value_map.CreatedDate": "123424",
    "user.key_value_map.Department.Name": "XYZ"
}

Code that worked for me:

function flattenObject(ob) {
    var toReturn = {};

    for (var i in ob) {
        if (!ob.hasOwnProperty(i)) continue;

        if ((typeof ob[i]) == 'object' && ob[i] !== null) {
            var flatObject = flattenObject(ob[i]);
            for (var x in flatObject) {
                if (!flatObject.hasOwnProperty(x)) continue;

                toReturn[i + '.' + x] = flatObject[x];
            }
        } else {
            toReturn[i] = ob[i];
        }
    }
    return toReturn;
}

Answer 5

This answer is an improvement of @Muthukrishnan 's answer

If you want to flatten an object deeply outputting the values into a one level deep object keyed with the path of the value in the previous object

(eg: { foo: { bar: 'baz'} } => { 'foo.bar': 'baz' })

Here is how you can effectively do it:

/**
 * @param ob Object                 The object to flatten
 * @param prefix String (Optional)  The prefix to add before each key, also used for recursion
 **/
function flattenObject(ob, prefix = false, result = null) {
  result = result || {};

  // Preserve empty objects and arrays, they are lost otherwise
  if (typeof ob === 'object' && ob !== null && Object.keys(ob).length === 0) {
    result[prefix] = Array.isArray(ob) ? [] : {};
    return result;
  }

  prefix = prefix ? prefix + '.' : '';

  for (const i in ob) {
    if (Object.prototype.hasOwnProperty.call(ob, i)) {
      if (typeof ob[i] === 'object' && ob[i] !== null) {
        // Recursion on deeper objects
        flattenObject(ob[i], prefix + i, result);
      } else {
        result[prefix + i] = ob[i];
      }
    }
  }
  return result;
}

/**
 * Bonus function to unflatten an object
 *
 * @param ob Object     The object to unflatten
 */
function unflattenObject(ob) {
  const result = {};
  for (const i in ob) {
    if (Object.prototype.hasOwnProperty.call(ob, i)) {
      const keys = i.match(/^\.+[^.]*|[^.]*\.+$|(?:\.{2,}|[^.])+(?:\.+$)?/g); // Just a complicated regex to only match a single dot in the middle of the string
      keys.reduce((r, e, j) => {
        return r[e] || (r[e] = isNaN(Number(keys[j + 1])) ? (keys.length - 1 === j ? ob[i] : {}) : []);
      }, result);
    }
  }
  return result;
}


// TESTS
const obj = {
  value: {
    foo: {
      bar: 'yes',
      so: {
        freakin: {
          nested: 'Wow',
        }
      }
    },
  },
  // Some edge cases to test
  test: [true, false, [null, undefined, 1]],
  not_lost: [], // Empty arrays should be preserved
  not_lost2: {}, // Empty objects should be preserved
  // Be careful with object having dots in the keys
  'I.like.dots..in.object.keys...': "... Please don't override me",
  I: {
    like: {
      'dots..in': {
        object: {
          'keys...': "You've been overwritten"
        }
      }
    }
  }
};
console.log(flattenObject(['I', {'am': 'an array'}]));
let flat = flattenObject(obj);
console.log(flat, unflattenObject(flat));

There is an obvious problem that you could encounter with flattening this way if your object contains keys with dots, this is documented in the fiddle

Answer 6

You could just concat all keys and values. (It does not solve the type casting to number for keys.)

var object =  { 0: [1, 2, 3, 4] },
    result = Object.keys(object).reduce(function (r, k) {
        return r.concat(k, object[k]);
    }, []);
    
console.log(result);