dropping trailing '.0' from floats

Question

I\'m looking for a way to convert numbers to string format, dropping any redundant \'.0\'

The input data is a mix of floats and strings. Desired output:

0

Answer 1

str(x)[-2:] == '.0' and int(x) or x

Answer 2

Using Python's string formatting (use str.format() with Python 3.0):

from decimal import Decimal

def format_number(i):
    return '%g' % (Decimal(str(i)))

Answer 3

To print a float that has an integer value as an int:

format = "%d" if f.is_integer() else "%s"
print(format % f)

Example

             0.0 -> 0
             0.1 -> 0.1
            10.0 -> 10
      12345678.9 -> 12345678.9
     123456789.0 -> 123456789
12345678912345.0 -> 12345678912345
12345678912345.6 -> 1.23456789123e+13
  1.000000000001 -> 1.0

Answer 4

I was dealing with a value from a json dictionary (returned by an API). All the above didnt help me so i constructed by own helper function. It truncates all the trailing zeros.

I Hope it helps someone out there

def remove_zeros(num):
    nums = list(num)
    indexes = (list(reversed(range(len(nums)))))
    for i in indexes:
        if nums[i] == '0':
            del nums[-1]
        else:
            break
    return "".join(nums)

num = "0.000000363000"
print(remove_zeros(num))

prints :

    0.000000363