dropping trailing '.0' from floats

Question

I\'m looking for a way to convert numbers to string format, dropping any redundant \'.0\'

The input data is a mix of floats and strings. Desired output:

0

Answer 1

So much ugliness out there…

My personal favorite is to convert floats that don't require to be a float (= when they actually are integers) to int, thus removing the, now useless, trailing 0

(int(i) if i.is_integer() else i for i in lst)

Then you can print them normally.

Answer 2

def floatstrip(x):
    if x == int(x):
        return str(int(x))
    else:
        return str(x)

Be aware, though, that Python represents 0.1 as an imprecise float, on my system 0.10000000000000001 .

Answer 3

from decimal import Decimal
'%g' % (Decimal(str(x)))

Answer 4

Following code will convert contents of variable no as it is i.e. 45.60. If you use str the output will be 45.6

no = 45.60

strNo = "%.2f" %no

Answer 5

>>> '%g' % 0
'0'
>>> '%g' % 0.0
'0'
>>> '%g' % 0.1
'0.1'
>>> '%g' % 1.0
'1'

Answer 6

>>> x = '1.0'
>>> int(float(x))
1
>>> x = 1
>>> int(float(x))
1