Printing the correct number of decimal points with cout

Question

I have a list of float values and I want to print them with cout with 2 decimal places.

For example:

10.900  should be prin         


        

Answer 1

setprecision(n) applies to the entire number, not the fractional part. You need to use the fixed-point format to make it apply to the fractional part: setiosflags(ios::fixed)

Answer 2

With <iomanip>, you can use std::fixed and std::setprecision

Here is an example

#include <iostream>
#include <iomanip>

int main()
{
    double d = 122.345;

    std::cout << std::fixed;
    std::cout << std::setprecision(2);
    std::cout << d;
}

And you will get output

122.34

Answer 3

Just a minor point; put the following in the header

using namespace std;

then

std::cout << std::fixed << std::setprecision(2) << d;

becomes simplified to

cout << fixed << setprecision(2) << d;

Answer 4

I had this similar problem in a coding competition and this is how I handled it. Setting a precision of 2 to all double values

First adding the header to use setprecision

#include <iomanip>

Then adding the following code in our main

  double answer=5.9999;
  double answer2=5.0000;
  cout<<setprecision(2)<<fixed;
  cout <<answer << endl;
  cout <<answer2 << endl;

Output:

5.99
5.00

You need to use fixed for writing 5.00 thats why,your output won't come for 5.00.

A short reference video link I'm adding which is helpful

Answer 5

Simplify the accepted answer

Simplified example:

#include <iostream>
#include <iomanip>

int main()
{
    double d = 122.345;
    std::cout << std::fixed << std::setprecision(2) << d;
}

And you will get output

122.34

Reference:

• std::fixed
• std::setprecision

Answer 6

#include<stdio.h>
int main()

{

 double d=15.6464545347;

printf("%0.2lf",d);

}