Press Enter to Continue

Question

This doesn\'t work:

string temp;
cout << \"Press Enter to Continue\";
cin >> temp;

Answer 1

You need to include conio.h so try this, it's easy.

#include <iostream>
#include <conio.h>

int main() {

  //some code like
  cout << "Press Enter to Continue";
  getch();

  return 0;
}

With that you don't need a string or an int for this just getch();

Answer 2

The function std::getline (already introduced with C++98) provides a portable way to implement this:

#include <iostream>
#include <string>

void press_any_key()
{
    std::cout << "Press Enter to Continue";
    std::string temp;
    std::getline(std::cin, temp);
}

I found this thanks to this question and answer after I observed that std::cin >> temp; does not return with empty input. So I was wondering how to deal with optional user input (which makes sense for a string variable can of course be empty).

Answer 3

Yet another solution, but for C. Requires Linux.

#include <stdio.h>
#include <stdlib.h>

int main(void) {
    printf("Press any key to continue...");
    system("/bin/stty raw"); //No Enter
    getchar();
    system("/bin/stty cooked"); //Yes Enter
    return 0;
}

Answer 4

Try:

char temp;
cin.get(temp);

or, better yet:

char temp = 'x';
while (temp != '\n')
    cin.get(temp);

I think the string input will wait until you enter real characters, not just a newline.

Answer 5

cout << "Press Enter to Continue";
cin.ignore();

or, better:

#include <limits>
cout << "Press Enter to Continue";
cin.ignore(std::numeric_limits<streamsize>::max(),'\n');

Answer 6

Replace your cin >> temp with:

temp = cin.get();

http://www.cplusplus.com/reference/iostream/istream/get/

cin >> will wait for the EndOfFile. By default, cin will have the skipws flag set, which means it 'skips over' any whitespace before it is extracted and put into your string.